Blocks taking a while to disappear

Help and Feedback Scripting Support
1

So my script puts a block into ReplicatedStorage to get rid of it for a couple of seconds. Put it takes about 2 seconds for it to actually disappear.

Code:

local AllColoursFolder = game.Workspace.Colours:GetChildren()
local function StartRound()
	wait()
	local randomColour = game.Workspace.Colours:GetChildren()[math.random(1, 2)]
	print (randomColour)
	changeColour(randomColour)
	Countdown()
	for i,v in pairs (game.Workspace.Colours:GetChildren()) do
		v.Parent = game.ReplicatedStorage

		randomColour.Parent = workspace.Colours

		wait(3)
		v.Parent = workspace.Colours

	end
end

Edit: It was meant to disappear on go and it also only happens sometimes…

2

If you need the scripts for the functions just say.

3

This happens because you have a for loop that waits. So every time it switches to a different part, it waits 3 seconds and parents the old part then moves to the new part.

Instead, you could make two different for loops and seperate them with a wait.

2 Likes
4

@ScarletHypernova’s solution is probably the best one for this problem

Here’s an example code so that you can understand it better:

local AllColoursFolder = game.Workspace.Colours:GetChildren()
local function StartRound()
	wait()
	local randomColour = game.Workspace.Colours:GetChildren()[math.random(1, 2)]
	print (randomColour)
	changeColour(randomColour)
	Countdown()
	
	local colours = game.Workspace.Colours:GetChildren() --or use AllColoursFolder defined above, as long as no children are changed beforehand
	for i,v in pairs (colours) do
		v.Parent = game.ReplicatedStorage
		randomColour.Parent = workspace.Colours --not sure why this one is in the loop so I'm leaving it here
	end
	wait(3)
	for i,v in pairs (colours) do --use the same "colours" variable to make sure only the same children are put back
		v.Parent = workspace.Colours
	end
end
5

Thank you all! Ill add it rn…

6

Also sorry I made extra variables lol.