Changing the value of a specific axis via a Script

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1

Is it possible to add/subtract the position value of a specific axis?

For example if a part has the Position of 0,0,0 how would it be possible to add to the x axis with a script so that the final position would be 5,0,0?

(Apologies if this doesn’t make much sense, it’s difficult to put it into words)

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2 
-- example

local pos = Vector3.new(0, 0, 0)
pos += Vector3.new(5, 0, 0)

print(pos) --> 5, 0, 0
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3

Yes this is very simple all you will need to do is get the Vector’s dimension axis and by using the operator += you can simply add on to the old val.

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4

Would it be possible to get the value of a specific axis? For example getting the value to the Y Axis?

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5 
local pos = Vector3.new(0, 0, 0)

-- pos.X / pos.Y / pos.Z
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6

You can try
Vector3.new(0 + 5, 0, 0)
No idea if this works, but if it doesn’t work then try
pos = pos + Vector3.new(5,0,0)

7

Essentially does the exact same thing.

Is the equivalent of saying:

Vector3.new(5, 0, 0)

@CaptainWeetabix
To add to a specific axis of a Vector3, you would simply add another Vector3 where only one axis is being added:

local pos = Vector3.new(0, 0, 0)
pos += Vector3.new(5, 0, 0)

print(pos) --> 5, 0, 0

When adding Vector3s together, each axis of each Vector3 will be added together, returning a new Vector3:

              x    y    z
-------------------------------
Vector3.new ( 0    0    0 )
              +    +    +
Vector3.new ( 5    0    0 )
-------------------------------
result:     ( 5    0    0 )

So to add only to the X axis of your Vector3, you would need to add Vector3.new(your_increment_here, 0, 0) to the current Vector3.

Vector3 API and math operations

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