# Converting a time number into bigger time number

Hey there,

I’m trying to convert like the Berezza method but I want to turn a number like

13,000 milliseconds into 13 S and 60,000 milliseconds into 1 Minute and etc to years and even more.

How can I do this?

use `math.floor()` for minutes and then take away the amount of minutes to seconds. For example:

``````local totalTime = 73
local minutes = math.floor(73/60)
local seconds = totalTime - (minutes*60)
``````

Wit this, you can add on and roundify with `math.floor()` until years.

Sorry but I don’t really understand how can I go to hours and days with this shematic…

Something like this?

``````local totalTime = 87000
local days = math.floor(totalTime/24)
local hours = math.floor(totalTime/60)
local minutes = math.floor(totalTime/60)
local seconds = math.floor(totalTime/1000)
local milliseconds = totalTime - (seconds*1000)
``````

It should looks like this? ;-:

Basically, `math.floor()` rounds a number so, 3.4 will be 3 after `math.floor()` Days and hours from seconds would be:

``````local totalTime = 100000
local days = math.floor(totalTime/86400)
local hours = math.floor(totalTime-(days*86400)/3600)
``````

for more reference, you can read this: https://developer.roblox.com/en-us/api-reference/lua-docs/math and find `math.floor()`

and the numbers I used to divide are the amount of seconds of this item.

For milliseconds I have to do :

``````totalTime = 100000
local days = math.floor(totalTime/86400*1000)
local hours = math.floor(totalTime - (days*(86400*1000) / 3600 * 1000)
local minutes = math.floor(totalTime - (days*(86400*1000) + hours*(3600*1000) / 60 * 1000)
local seconds = math.floor(totalTime - (days*(86400*1000) + hours*(3600*1000) + minutes * (60*1000) / 1000)
local milliseconds = totalTime - (days*(86400*1000) + hours*(3600*1000) + minutes * (60*1000) + seconds * 1000)

``````

that’s it?

Yes, that’s right. Years stack up the same way.

And how should I return the obtained String?

The returned items are integers, and remote events is a good way.

You can probably look into this instead: https://developer.roblox.com/en-us/api-reference/lua-docs/os

No it’s not what I’m looking for

I think i will make a function into my TextLabel local script wich shows the value of the time (it is a currency)

So at the end of this function I wrote upper,
Will it works?

You can return totalTime and convert locally. I’m not sure to understand what you mean.

Something like this

``````local function AbbreviateTimeNumber(Number)
local days = math.floor(Number/86400*1000)
local hours = math.floor(Number - (days*(86400*1000) / 3600 * 1000)
local minutes = math.floor(tNumber - (days*(86400*1000) + hours*(3600*1000) / 60 * 1000)
local seconds = math.floor(Number - (days*(86400*1000) + hours*(3600*1000) + minutes * (60*1000) /
1000)
local milliseconds = Number - (days*(86400*1000) + hours*(3600*1000) + minutes * (60*1000) + seconds * 1000)

return Number
end

So number will be something like 13 Days?``````

I think you should return everything. Number will still be the amount you entered in front of the function.

``````local plr = game:GetService("Players").LocalPlayer
local Timestamps = plr.PlayerInfo.Timestamps

script.Parent.Text = Timestamps.Value

Timestamps:GetPropertyChangedSignal("Value"):Connect(function()
script.Parent.Text = Timestamps.Value
end)
``````

This is my script, I want to replace the milliseconds by shorter number like days etc… by calling the function I wrote and the text will be equal to the returned value

so let’s say 100000 miliseconds, it will be shortened to x years, y days, etc.? If so, the best way would be returning everything, or returning a string with all the values.

Yeah that’s the idea
(30 chars

Ok so I have to return the highest (idk how to call it (days / hours / etc…) and to add a coma “,” and to add the second one so,

If you have 3 days and 7 hours you want the script to do

local returnedNumber = days…","…hours…" Days"

So it will return “3,7 Days”

It should be something like this:

``````if years == 0 and days == 0 then --if statement to know which category to class
return days+"".."days, "..hours+"".."hours, " --etc
elseif
end
``````

Hope this helps, sorry for late response tho