Function highlighted orange in task.spawn

[Violet_sheer (TheOtherSider)]

local function f1()
	local var = false
end


function f2()
	local var = true
end

task.spawn(function()
	local function f3()
	end
	function dasondon()
		print("Success")
	end
end)

The function dasondon is underlined orange, any ideas?

[4UnderscoreRa]

It may want you to define it outside of task.spawn, but also the function could be local to another running instance depending on how you defined it.

[Violet_sheer (TheOtherSider)]

Yeah I think its because I’m using a global function in a task.spawn function in which the task.spawn function creates a new thread while seperating from my current one.

[4UnderscoreRa]

mark mine as solution <3
characters

[Violet_sheer (TheOtherSider)]

I didn’t get the solution from that because it does want me to define it outside of the task.spawn function but its because the task.spawn function is creating a new thread.