Functions question

Help and Feedback Scripting Support
#1 
function A()
B()
end

function B()
end

i assume something like this would not work because of sequencing? or would it? would i have to define function B() first?

#2

I believe you have to define it first. I could be wrong though.

#3

Maybe this would help

Returning a function inside another function - Help and Feedback / Scripting Support - DevForum | Roblox

#4

define function B() first then you can potentially call function B() from function A()

function B()
end

function A()
B()
end
#5

You shouldn’t have to define it first? As it’s not a local function, so sequence doesn’t matter I believe.

This works:

function A()
	B()
end

function B()
	print("B printed")
end

A()
2 Likes
#6

I just wanted to add on that recursion, a function calling upon itself as a function, is possible as long as it can be calculated. For example:

function calculate(number)
	if number + 2 == 12 then -- if the inputted number + 2 is 12 then we cool
		print("nice, we got twelve")
	else -- if not, try again using this function so we don't gotta retype all that nasty code
		print("trying again...") 
		calculate(number+2)
	end
	
end

calculate(2) -- will start calculating until it is 12