Help with Number Conversion Script

[Vehold]

Can someone word, or explain the mathematical aspect happening in this part of the Number Conversion script? thank you

math.floor(p1/(10^((v2-1)*3)/100))/100 … u1[v2]

Conversion Script:

local u1 = {"", 'K', "M", "B", "T", "Qa", "Qi", "Sx", "Sp", "Oc", "No", "Dc"}
function v1(p1)
	for v2 = 1, #u1 do
		if tonumber(p1) < 10 ^ (v2*3) then
			return math.floor(p1/(10^((v2-1)*3)/100))/100 .. u1[v2]
		end
	end
end

[Kaid3n22 (Kaiden)]

Well, let’s say the number is 100. The v2 number would be 1.
here

@Vehold

(v2-1)

we subtract 1 from it, so we get 0.

@Vehold

(v2-1)*3

multiply it by 3, it would still be 0
By order of operations, we then do the exponential part (10^0), which is 1.

@Vehold

10^((v2-1)*3)

Next, we will divide by 100 and get 0.01

@Vehold

(10^((v2-1)*3)/100)

lastly, we do 100/0.01, which leads to 10000 and do math.floor to remove any decimals

@Vehold

math.floor(p1/(10^((v2-1)*3)/100))

Divide by 100, and you get 100 again.

@Vehold

math.floor(p1/(10^((v2-1)*3)/100))/100

Lastly, add the correct prefix.

@Vehold

math.floor(p1/(10^((v2-1)*3)/100))/100 .. u1[v2]

This is the best way I can explain it, which is just the simple process of solving the equation with substitution on knowing what the numbers would be, but I hope this helps!