How can i detect if two rotated guiObjects are touching?

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#1

So I’ve made something that tells me if two non-rotated guiObjects are touching each other or not but i do not know how i can make it work for rotated frames. Here is the code

local s=script.Parent.small
local b=script.Parent.big
s:GetPropertyChangedSignal('Position'):Connect(function()
local biggerv=math.max(s.AbsolutePosition.X,b.AbsolutePosition.X)==s.AbsolutePosition.X and s or b
local smallerv=math.min(s.AbsolutePosition.X,b.AbsolutePosition.X)==s.AbsolutePosition.X and s or b
local biggervY=math.max(s.AbsolutePosition.Y,b.AbsolutePosition.Y)==s.AbsolutePosition.Y and s or b
local smallervY=math.min(s.AbsolutePosition.Y,b.AbsolutePosition.Y)==s.AbsolutePosition.Y and s or b
local resX=smallerv.AbsolutePosition.X+smallerv.AbsoluteSize.X<=biggerv.AbsolutePosition.X+biggerv.AbsoluteSize.X and smallerv.AbsolutePosition.X+smallerv.AbsoluteSize.X>=biggerv.AbsolutePosition.X or biggerv.AbsoluteSize.X<=smallerv.AbsoluteSize.X and smallerv.AbsolutePosition.X<=biggerv.AbsolutePosition.X and biggerv.AbsolutePosition.X+biggerv.AbsoluteSize.X<=smallerv.AbsolutePosition.X+smallerv.AbsoluteSize.X
local resY=smallervY.AbsolutePosition.Y+smallervY.AbsoluteSize.Y<=biggervY.AbsolutePosition.Y+biggervY.AbsoluteSize.Y and smallervY.AbsolutePosition.Y+smallervY.AbsoluteSize.Y>=biggervY.AbsolutePosition.Y or biggervY.AbsoluteSize.Y<=smallervY.AbsoluteSize.Y and smallervY.AbsolutePosition.Y<=biggervY.AbsolutePosition.Y and biggervY.AbsolutePosition.Y+biggervY.AbsoluteSize.Y<=smallervY.AbsolutePosition.Y+smallervY.AbsoluteSize.Y
if resX and resY then
	s.Position=UDim2.fromScale(0,s.Position.Y.Scale)
	game:GetService('TweenService'):Create(s,TweenInfo.new(10,Enum.EasingStyle.Linear,Enum.EasingDirection.Out,-1,false,0),{Position=UDim2.fromScale(1,s.Position.Y.Scale)}):Play()
end
end)
game:GetService('TweenService'):Create(s,TweenInfo.new(10,Enum.EasingStyle.Linear,Enum.EasingDirection.Out,-1,false,0),{Position=UDim2.fromScale(1,s.Position.Y.Scale)}):Play()
#2

Unfortunately, I don’t know the math well enough to explain in this answer, but there is a nice resource on stack overflow that goes over the problem. They also provide the source code and illustration for how it works.

#3

Thank you for replying! I’ll read it as soon as possible!