### (I just realized you can use the Y value of the normal vector rather than normal:Dot(0,1,0), I will keep the full unsimplified answer for anyone else who may need help with a similar problem)

Here is the simplified answer:

```
math.acos(normalVector.Y)
```

(This is the long answer before I realized it could be shortened, but only in this one case)

You could probably simply do:

```
math.acos(normalVector:Dot(Vector3.new(0,1,0)))
```

:Dot() means dot product, which is the operation of projecting the tip of one vector onto the other at a right angle to the other, and returning the distance to that projected point from the origin

This can be seen in the image above, where the tip of A is projected, at a right angle, to B. The distance of the green line is then the result of A:Dot(B)

To complete the question, and find angle α, we have to introduce some trig

A•B is another, more mathematical representation of the dot product of two vectors (no its not one of the many symbols for multiplication that noone can seem to decide on)

What the above formula basically means, is that the output of the function cos of angle α is equal to the length of the side adjacent to angle α divided by the length of the hypotenuse of the right triangle, which is, in our case, A•B and 1 respectively

You can then use the inverse cosine, acos or arccosine to solve for α, giving you this final formula:

(The /1 can just be ignored because anyting /1 is just itself)

This is the formula given at the beginning of the post

This should result in the incline angle on a slope