# How I Can Pet Movement Inverse Circle Position

How I Can Pet Movement Inverse Circle Position

I Want:

My Script:

My Code:

``````local radius = 10

local function getCirclePoint(ItemNumber,TotalNumber)
return (ItemNumber * ((2 * math.pi) / TotalNumber))
end

local angle = getCirclePoint(i,#petsTable)
local position = (hmndrootpart.CFrame * CFrame.new(math.sin(angle) * radius, 0 , math.cos(angle) * radius))

v.PrimaryPart.CFrame = position
``````

what ? .-.-…-.-.-.-.-.-.-.-.-.-.

Try replacing this

With this

``````return (ItemNumber * ((math.pi) / TotalNumber))
``````

## Why?

180deg is `math.pi`,
360deg is `math.pi*2`,

again giving error

idk .-.-.-.-.–.-.-.-.-.-.-.-.-

Oh wait oops, do this

``````return (ItemNumber * math.pi)
``````

(Only do this if your pets are 2 or below other wise use `math.pi*2/total_pets`)

``````local function getCirclePoint(ItemNumber,TotalNumber)
if TotalNumber <= 2 then
return (ItemNumber * math.pi)
else
return (ItemNumber * ((2 * math.pi) / TotalNumber))
end

end
``````

.p again

``````local position = CFrame.new(hmndrootpart.CFrame * Vector3.new(math.cos(angle) * 5, 0, math.sin(angle) * 5))
``````

only 2 position ??

I told you before.

three part problem

Hmmm thats weird
working for me

Why are you using pi if your not wanting it to be in a circle.

It needs to be in circle.
`pi` = 180 degs (pets at left and right)
`pi * 2` = 360 degs (pets in all directions)

This is not in a circle

sorry if im starting another argument

This is a circle, those pets are at 180 deg.

ohh sorry for interrupting.

1 Like

``````local function getCirclePoint(ItemNumber,TotalNumber)