How to check if table has more than one element?

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1

Lets say I have a table, with 1 element. Then I insert another element into the table. I want to check if table has more than one element, I delete the 1st element and replace it with the second. I know how to remove elements from tables and add, but I don’t know how to check if it has more than 1 element in it. Do I use table.find()?

2

You could do table.find to find another element if you want

3

Though you could also learn OOP in this case with index and stuff. Making metatables

4

You can use # operator:

local tab = {"apple", "bannana"}
print(#tab) --> 2
5

I think you want the length of the table, which you can get by doing
#exampletable
In you case it would be

if #exampletable > 1 then
    exampletable[1] = exampletable[2]
    exampletable[2] = nil
end
6

This would result in a lot of if statements if he did this

7

He would need to insert the stuff in the table manually I think he’s inserting it through scripts then trying to find it, etc in which case table.find is his solution if that is true.

8

Uh no? If you want to shift everything over 1 place

for i = 1, #table do
    table[i] = table[i+1]
end
1 Like
9

(As others have mentioned)
The # literally gets the amount of elements (Or length depending on how you look at it) in a table, table.find should only be necessary if you want to check for a certain value to find while #Table can check if you’re excluding the amount of objects in a table:

local Table = {"I am a string", 50, true, workspace.Baseplate}
print(#Table) 

if #Table > 1 then
    print("Yes")
end

For this:

Just use the table.insert/remove functions to add/remove what you want

local Table = {"I am a string"}

table.insert(Table, "I am yet another string")
print(#Table) 

if #Table > 1 then
    print("Yes")
end
10

table.remove automatically shifts everything, use that. It should be faster than anything you can write.

11 
if #table > 1 then
  --code
end