How to find how many times a number can divide another?

[DisksjwYT (Disksjw)]

Basically, I need to see how many times a number can divide another number before becoming a decimal.

81 can be divided by 3 4 times.
81 / 3 = 27
27 / 3 = 9
9 / 3 = 3
3 / 3 = 1
But how would I put that into code?

[bioeless (BI0LESS)]

Here:

function NumberOfDivides(num1: number, num2: number): number
	local result = num1
	local count = 0

	while result == math.floor(result) do
		result = result / num2
		count += 1
		if result == num1 or result == 1 then
			if count == 1 then
				result = "-1" -- -1 means infinite
			end
			break
		end
	end

	return count
end

[Stratiz]

The function I wrote will give you the number of divisions until it becomes a decimal or reaches 1.

local function NumberOfDivisions(numberToDivide : number, divideBy : number) : number
	local numberOfDivisions = 0
	while true do
		numberToDivide /= divideBy
		if numberToDivide % 1 == 0 then
			numberOfDivisions += 1
		end

		if numberToDivide <= 1 then
			break
		end
	end

	return numberOfDivisions
end

print(NumberOfDivisions(81, 3)) --> 4
print(NumberOfDivisions(27, 3)) --> 3
print(NumberOfDivisions(1, 10)) --> 0

[SeargentAUS (Seargent)]

I know that a solution has already been marked for this post, but I feel like the previous replies complicate matters, when it could be a single line of code:

local function NumberOfDivisions(num1, num2)
    return math.floor(math.log(num1, num2))
end

[DisksjwYT (Disksjw)]

@PoppyandNeivaarecute

local function NumberOfDivisions(num1, num2)
    return math.floor(math.log(num1, num2))
end

I didn’t even know this was possible. Thank you!

[Stratiz]

Whoops, I forgot logarithms exist, haha. Great answer!