Is code after task.spawn() guaranteed to execute after the code in the spawn?

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1 
task.spawn(print, 1)
print(2)

Is that guaranteed to print in this order:

1
2

Or is that a race condition?

2

task.spawn() will run first and then print() will

unless im being stupid and should go to bed

3

task.spawn will be called before the print, but will the first print being called by task.spawn with 1 run before the 2nd print being called with 2?

4

Yes. The only scenario where task.spawn wouldn’t execute is if you’re at a recursion depth of 200. Otherwise, it’s immediate and the output would look like this:

1
2
5

if you’re not sure, then you can use task.defer, but it might vary really, while developing my signal module i encoutered a problem where sometimes if the game’s memory usage is higher due other scripts, my :Once() function didn’t worked, this is why i implemented :safeOnce() and :call() that wouldn’t use task library, tho it’s just an observation