Is there a way to use part of name to get item in table?

Help and Feedback Scripting Support
,
1

i’m trying to split the string of something in a table but to call the item in the table i only have half the name confirmed and was wondering if their was a way to still get the correct item?

Blockquote

if data ~= nil then
print(data)
for i, v in pairs(DataStuff:GetChildren()) do
print(v)
local Need = tostring(v)
local splitString = string.split(data[Need], “@”)
print(splitString)
local Exp = splitString[2]
print(Exp)
local XpR
local Lvl
end
else
for i, v in pairs(DataStuff:GetChildren()) do
v.Value = 0
end
end

2 
if data ~= nil then
	print(data)
	for i, v in pairs(DataStuff:GetChildren()) do
		print(v)
		local Need = tostring(v)
		local splitString = string.split(data[Need], “@”)
		print(splitString)
		local Exp = splitString[2]
		print(Exp)
		local XpR
		local Lvl
	end
else
	for i, v in pairs(DataStuff:GetChildren()) do
		v.Value = 0
	end
end

I’m fairly certain you have both the name and half the name
Full name: local Need = tostring(v), and (maybe) v
Half name: local splitString = string.split(data[Need], “@”)
Not really sure what you want to accomplish so I’d appreciate if you add more details

3

basically what i’m doing is getting the name of a variable but to save it i made it one thing so the name and value are split between an @ symbol but to call it i’m trying to know if there’s a way to call it using only the stuff before the @ since it would be unknown

4

when you call string.split() it returns a table of the string split by whatever you splitted it by (no duh).

Lets say data[Need] = "Water@Door" and you do this:
local splitString = string.split(data[Need], “@”),
splitString should equal {"Water", "Door"}.

Assuming there’s just 1 “@” symbol in data[Need] where it splits the string in half, you should do splitString[1] to access the first half and splitString[2] to get the other half.

When you say

You’d be wrong, since it is known? So unless I’m getting something wrong, I’m pretty sure you still have both the names

5

example:

the thing I’m trying to find is called swordXp@28

all i know is swordXp@ and i need to call the whole swordXp@28 but i don’t know what the 28 is because it’s the part I’m trying to get when i split it…
what I’m trying to find out is if there is a way to get the whole name using only the swordXp@ because i only learn what’s after the @ once i split it

the issue i’m trying to fix is that when i say local splitString = string.split(data[Need], “@”)
and i’m trying to get swordXp@28, Need in " `local splitString = string.split(data[Need], “@”)" is just swordXp@ because i don’t know what comes after @

6

Can you fix this last sentence? I think I’m starting to understand it but the last sentence kinda confuses me

7

String.split returns an array of strings so simply index two of the array and you will get “28” as a string if you need it as a number use the tonumber() function

SplitString = string.split(“swordXp@28”, “@“)[2]

8

that work?
Need in " `local splitString = string.split(data[Need], “@”)" is just swordXp@ because i don’t know what comes after @