Making a time counter for a daily reward claim system!

Help and Feedback Scripting Support
#1

Hey there!

I’m making a Daily Reward system and I watched a lot of videos on it, everything is working but I want to make a chrono under the dailyReward to know if you can claim it or how much time you have to wait.

So i went on a function like this:

local function convertTime(n)
	local String
	local hours = (math.floor(n / 3600))
	local minutes = (math.floor((n - (hours*3600)) / 60))
	local seconds = (math.floor(n-(hours*3600)-(minutes+60)))
	if hours <= 9 then
		hours = "0"..hours
	end
	if minutes <= 9 then
		minutes = "0"..minutes
	end
	if seconds <= 9 then
		seconds = "0"..seconds
	end
	if hours ~= 0 and minutes ~= 0 and seconds ~= 0 then
		String = hours..":"..minutes..":"..seconds
	else
		String = "Ready to claim!"
	end
	return String
end

while wait(1) do
	if lastClaim then
		text.Text = convertTime(os.time() - lastClaim)
	end
end

So it gives me the time between the last Claim so I give me 35 minutes and 2000 seconds it’s why I don’t understand ;-:.

So How can I fix this to give me something like : “Next in: 09:57:30”.

Thank you!

#2

Oh okay, when I red me back I found an issue wich fix the seconds problem.
It comes from the line:

local seconds = (math.floor(n-hours*3600)-(minutes+60)))

I replaced the “+” by the “*”

#3

But I still need help to find how can i get the time remaining instead of the past time between the lastClaim and now

#4

if the claim must be exactly 24 hours later, this could work

text.Text = convertTime((24*60*60) + lastClaim - os.time())
1 Like
#5

Hey!

I just find my solution!

Thank you for your help!

1 Like