so here is what i’m trying to accomplish;
https://gyazo.com/0f999cc4c20243a0c8d9a55f3b1d50b0

i have a hatch time which decides when the hatch will be completed etc, i need that effect to be done in that time

let me send my current code;

(The Problem is the “ActualWait” variable in the script)

for i = 1, AmountOfHits do
local normalizedIndex = i / AmountOfHits
local ActualWait
local HitDirection

local Directions = {
["Right"] = -1,
["Left"] = 1
}

if LastHitDirection == "Right" then
HitDirection = "Left"
else
HitDirection = "Right"
end

-- THE ACTUAL PROBLEM, WHICH NEEDS TO BE CHANGED
ActualWait = HatchTime * math.exp(-i / 4)

local Force = math.abs((i - AmountOfHits) * 1.8) * Directions[HitDirection]

TS:Create(newCFrame, TweenInfo.new(ActualWait), {Value = WantedValue}):Play()

local WantedScale = i  / 92
if i < (AmountOfHits  / 2) then

TS:Create(ScaleNumber, TweenInfo.new(ActualWait / 1.5, Enum.EasingStyle.Back), {Value =  WantedScale + ScaleNumber.Value}):Play()
else
-- dont rlly mind this part
ScaleCompleted = true
TS:Create(ScaleNumber, TweenInfo.new(ActualWait, Enum.EasingStyle.Linear), {Value = 0.1}):Play()
end

LastHitDirection = HitDirection
wait(ActualWait)
end

Completed = true

end)

So the first thing is that if hatch time is like 2 then this takes 10 seconds to accomplish
and so yeah, i’d appreciate it if someone could provide some useful math formula or something for this

Couldn’t you just do HatchTime * 5?

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