(removed by post author)

Help and Feedback Scripting Support
1

(removed by post author, until later notice)

2

To round you may use math.round() as it is the same as math.floor(x + .5).

I believe using modulo may be an appropriate approach, it will give you what is missing to make it evenly divisible.

If you have an increment of 2 then only numbers divisible by 2 would be allowed. I think you might be able to do something like this:

function f(inc, val)
	val = math.round(val)
	local diff = val % inc
	return math.round(val + diff/2)
end

print(f(2, 2.5)) -- Prints 4

This is not exactly what you wanted, but this is a perhaps a good starting point for you. Currently it will round anything from from .5 and up to the next interval, but you can probably fix this with some minor adjustments.

1 Like
3

Not exactly true. math.round() rounds up or down while math.floor() will only round down

4

Yes, but adding .5 to any value inside of it will round it up or down.

math.floor(x + .5) -- Expression
-- Examples:
math.floor(.3 + .5) -- = 0.8 => 0 [math.round(0.3) => 0]
math.floor(.4 + .5) -- = 0.9 => 0 [math.round(0.4) => 0]
math.floor(.5 + .5) -- = 1 => 1 [math.round(0.5) => 1]
math.floor(.9 + .5) -- = 1.4 => 0 [math.round(0.9) => 1]
5

(removed by post author, until later notice)

1 Like
6 
local function RoundNumberToNearestMultipleOfN(Number, N)
	return math.floor(Number / N) * N
end

print(RoundNumberToNearestMultipleOfN(15, 7)) --14
print(RoundNumberToNearestMultipleOfN(10, 3)) --9
7

Shouldn’t 2.5 round down to 2 not up to 4? Assuming you want to snap a value to a grid of values.

Check my reply above.

8

Yes, it should.

However, since 4.5 will round to 6 it will still be 2 units of space, just offset in a dumb way.