local suffixes = {'','K','M','B','T','qd','qn','sx','Sp','O','N','de'}
local function format(val)
for i=1, #suffixes do
if tonumber(val) < 10^(i*3) then
return math.floor(val/((10^((i-1)*3))/100))/(100)..suffixes[i]
end
end
end
In my opinion this is much better