I am confused why it returns that 1,1 when . clearly resides at the 4th index not the first?
Change it to:
local a, b = string.find("lol.com", "%.")
The reason for needing the percent sign is to escape the string pattern. The . character is a string pattern which means any character. Therefore, it is getting the letter “l,” rather than the desired “.”
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Oh right I forgot . was a string pattern my bad lol, thanks cuz the % nullifies the effect as a string pattern and searches for the string literally, thanks 
You should mark my response as solution. Thanks and good luck! 
Thank you so much and good luck aswell!(will mark as response)