Unable to assign property Text. string expected, got boolean

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1

I was trying to create a cooldown for some abilities on a weapon I created, and I got this error.

This is the code where I made the cooldown:

138    for i,v in pairs(abils:GetChildren()) do
139 		if v:FindFirstChild("Cooldown") then
140 			v.Cooldown.Text = v.Name == "Dive" and (tick()-var.diveTick) or v.Name == "Teleport" and (tick()-var.teleportTick)
141 			v.Cooldown.Visible = v.Name == "Dive" and tick()-var.diveTick > 0 or v.Name == "Teleport" and tick()-var.teleportTick > 0
142 			if v.Name == "Leap" then v.Cooldown.Visible = false end
143 		end
144 	end

The error is at line 140.
Let me know if you need any other information! Any help would be greatly appreciated.

2

Try changing this snippet to this:

v.Cooldown.Text = (v.Name == "Dive" and (tick()-var.diveTick)) or (v.Name == "Teleport" and (tick()-var.teleportTick))

Parentheses matter in situations such as this

1 Like
3

You need a fallback here, if both conditions evaluate to false, the final condition will then be false, thus producing the error. So just add some random fallback like or 0 and you should be good to go. Parentheses also may or may not help as HugeCoolBoy said

v.Cooldown.Text = (v.Name == "Dive" and (tick()-var.diveTick)) or (v.Name == "Teleport" and (tick()-var.teleportTick)) or 0

Btw in Luau there is a feature called “if-then-else” expressions which act as a proper ternary operator if you’re looking for something more idiosyncratic:

v.Cooldown.Text = if v.Name == 'Dive' then tick() - var.diveTick
    elseif v.Name == 'Teleport' then tick() - var.teleportTick
    else 0
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4

I will make sure to remember this information, thank you!

5

Thank you, this fixed the issue! I ended up recoding the part where it sets the text because it counted the opposite way I wanted it to, but you did help me!

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6

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