I fail to understand why this returns “a” instead of nil.
print(string.match("acx1",".")) -- prints "a"
string.match looks for the first match of pattern in the string s. If a match is found, it is returned; otherwise, it returns nil. A third, optional numerical argument, init, specifies where to start the search; its default value is 1 and can be negative.
This does not answer my question. it should return nil in this case, I must be missing something.
I think it’s returning nil because you are forgetting to provide all three parameters for string.match.
The first parameter is s for string, the second is pattern which is a string, and third is init which is a number defaulted at a value of 1.
This may also help:
It does not return nil it returns “a”, please read my post.
You should read the help on patterns. A period means it will match any single character, in this instance the ‘a’.
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