Yes, like in the picture… ahh thirty ch
Alright lemme try and get this 100% correct.
- You want to have 3 count downs at the same time
- When one countdown is finished it goes to the bottom and stays at [ 0:00:00 ]
- Then the other count downs just move up the line
So is like this
Just consider this is surface gui with 3 text labels and this is the text
Event A [1:00:00]
Event B [2:00:00]
Event C [3:00:00]
They gonna countdown right? all three… With their numbers too…
And after Event A finish, Event B move to the top with [1:00:00] obviously because an hour and Event C to the middle and Event A becoming on the bottom with [3:00:00]
Repeat the same process for event B, until become 0, becoming to the bottom with 3:00:00 and Event C move to the top, A in the middle
And loop
Whelp after a hour of coding and a lot of miss takes I think I finally have your solution.
YESSS, can you give the script? Thank youu
Oh yea, can this work even if no player in the server? Well just asking. But yeah what I ask the first time is like what you showed me, this question is just for a bonus question.
For your question once the server is up then the code will run.
I just need to mention this that in the line of code:
local Time
local Time2
local Time3
They need to be from the lowest to the highest a.k.a. ascending order
local h = 0
local m = 0
local s = 0
local formula
local SBB = workspace.TimePlace.SurfaceGui
local topBuildBoard = SBB.GlobalTime
local MiddleBuildBoard = SBB.TimeLeft
local BottomBuildBoard = SBB.c
local va = topBuildBoard.Position
local vb = MiddleBuildBoard.Position
local vc = BottomBuildBoard.Position
local Time = 10 -- Time, Time2, Time3 are 5 seconds apart
local Time2 = 15
local Time3 = 30
local debounce = 1
function CountDown(number) -- gives us the number converted into time
h = 0
m = 0
s = 0
for i=1, number do
s = s + 1
if s == 60 then s = 0
m = m + 1
end
if m == 60 then m = 0
h = h + 1
end
end
end
function LooperfunctionA(Time:number, any:"function", text:string, item) -- fires a function after the loop
local stop = os.time() + Time
local num = 0
local formula
--Before the loop
repeat
CountDown(Time)
Time -= 1
formula = h.. ":".. m.. ":".. s
item.Text = "Event "..text.." [".. formula.. "]"
-- if you don't want the function to play
-- within the loop then move it to before
task.wait(1)
until
stop < os.time()
debounce += 1
if any then any(debounce) end
--After the loop
print("finished function! :D")
end
function Refresh(check)
if check == 1 then
topBuildBoard.Position = va --topBuildBoard.Text = "Event A "
MiddleBuildBoard.Position = vb --MiddleBuildBoard.Text = "Event B "
BottomBuildBoard.Position = vc --BottomBuildBoard.Text = "Event C "
end
if check == 2 then
topBuildBoard.Position = vc; --"Event B "
Time = math.max(Time, Time2, Time3)
MiddleBuildBoard.Position = va --"Event C "
BottomBuildBoard.Position = vb --"Event A "
end
if check == 3 then
topBuildBoard.Position = vb --Text = "Event C "
Time2 = math.max(Time, Time2, Time3)
MiddleBuildBoard.Position = vc --Text = "Event A "
BottomBuildBoard.Position = va --Text = "Event B "
debounce = 0 -- resets it back to the beginning
end
end
task.wait(8)
coroutine.wrap(function()
while true do
LooperfunctionA(Time, Refresh, "A", topBuildBoard)
end
end)()
coroutine.wrap(function()
while true do
LooperfunctionA(Time2, Refresh, "B", MiddleBuildBoard)
end
end)()
while true do
LooperfunctionA(Time3, Refresh, "C", BottomBuildBoard)
end
--Output will most likely look like :
-- Event A 1:15:23
-- Event B 2:15:23
-- Event C 3:15:23
Ah so if lets say in the future i want to well u can say update or upgrade it, i need use os.time i suppose?
I already put you as a solution but this question is just for curious cause i’m a new dev.
Depends on how you want to upgrade it, but overall I only used os.time() once in the script so I’m not too sure. Might be because my brain hurt from how many times I’ve already upgraded it. 
Well how i want to upgrade in the future honestly is more like soo even when there’s no player it still countdown so i can like broadcast to my group and says “Event A start from 0:00 UTC and event B start at 01:00 UTC, Event C start at 02:00 UTC, and it will repeat, after Event C finish, Event A will start again at 03:00 UTC and so on continue.
Sadly I just don’t see that possible without a single server being up and running so the code can be executed. “No players, no reason for a server.”, Basically a explanation for roblox servers.