Disabling Script Timeout?

[Varsitelle]

Hello, I’m wondering how I can run loops like these…

local OneMillion = 1000000
local clock = os.clock()
for i = 1, OneMillion do
   -- test()
end
print("Time", os.clock() - clock)

without this

-- 13:05:35.119  Script timeout: exhausted allowed execution time  -  Server - Script:7

Interrupting that specific loop.

Edit:

local function test()
   -- etc..
end

-- vs

local test = function()
   -- etc..
end
-- Preferences/Readibility vs Optimization

They should finish at similar times.

[SOTR654]

Add wait()

local OneMillion = 1000000
local clock = os.clock()
for i = 1, OneMillion do 
   wait()
   -- test()
end
print("Time", os.clock() - clock)

[Stone_lord123]

using wait(0) also works well.

Im fairly certain it gives a delay of about 25 miliseconds.

[Afraid4Life (Afraid)]

If you want to increase the number as well, you need to add the increment to the for loop
for example:

local OneMillion = 1000000
local clock = os.clock()
for i = 1, OneMillion, 1 do -- Third value is the increment, in this case we're adding one 
   -- test()
   wait()
end
print("Time", os.clock() - clock)

[Varsitelle]

I don’t want the loop to have a delay. I’m testing for different speed rates on functions that do similar tasks. Choosing which one is the fastest.

@Afraid4Life
Yes I know that, the default is 1 which is what I’m planning on using.

[Afraid4Life (Afraid)]

im pretty sure if you don’t want to have that delay then you’re going to have to add the increment.

[Varsitelle]

game.Players V.S. game:GetService("Players") Whats the difference?

The title says it all. So basically what’s better when using a service? game:GetService(“SomeService”)? Or game.SomeService? Which one should I use?

@Halalaluyafail3

There are a few reasons people use GetService,

• Names of services aren’t the same as the ClassName (ex: UserInputService)
• Not all services are already created (ex: Teams)

I’m not sure about the speed, but maybe you can check using tick()

This shouldn’t be an issue when accessing services, considering you should only need to get them once.

But anyways, I did a test with a ton of methods on how to get ServerStorage.

Code

local t = tick()
for i=1,100000 do
	local s_storage = game.ServerStorage
end
print("index",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:GetService"ServerStorage"
end
print("GetService",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:getService"ServerStorage"
end
print("getService",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:FindService"ServerStorage"
end
print("FindService",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:findService"ServerStorage"
end
print("findService",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:service"ServerStorage"
end
print("service",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:FindFirstChild"ServerStorage"
end
print("FindFirstChild",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:findFirstChild"ServerStorage"
end
print("findFirstChild",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:FindFirstChildWhichIsA"ServerStorage"
end
print("FindFirstChildWhichIsA",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:findFirstChildWhichIsA"ServerStorage"
end
print("findFirstChildWhichIsA",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:FindFirstChildOfClass"ServerStorage"
end
print("FindFirstChildOfClass",tick()-t)
local t = tick()
for i=1,100000 do
	local s_storage = game:findFirstChildOfClass"ServerStorage"
end
print("findFirstChildOfClass",tick()-t)

And the results

  index 0.076725721359253
  GetService 0.054219484329224
  getService 0.054208040237427
  FindService 0.041592121124268
  findService 0.054868221282959
  service 0.055800437927246
  FindFirstChild 0.082368850708008
  findFirstChild 0.08403754234314
  FindFirstChildWhichIsA 0.32629704475403
  findFirstChildWhichIsA 0.35951209068298
  FindFirstChildOfClass 0.16426634788513
  findFirstChildOfClass 0.19518733024597

From the results, it appears that FindService is the best method, but it still suffers from the issue of services not existing, although it won’t throw an error immediately.

[SOTR654]

Hmm… Could use coroutines.

local OneMillion = 1000000
local clock = os.clock()
local Function = coroutine.create(function()
    -- Code --
end)
for i = 1, OneMillion do 
    coroutine.resume(Function)
end
print("Time", os.clock() - clock)

It would be instantaneous.

[Varsitelle]

I could but the time the function took to run 1 million times won’t be recorded.

[SOTR654]

Maybe this:

local OneMillion = 1000000
local clock = os.clock()
for i = 1, OneMillion do
    wait(1)
    -- test()
end
print("Time", os.clock() - clock - OneMillion)

This should give what you want.

[x86_architecture (TritiumAndDeuterium)]

You can’t disable script timeout, but you can add a yield/wait to a loop to stop it.

[comsurg (cog)]

Timeouts exist so that the script didn’t delay task manager too much.