Get number name from number?

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#1

Is there a function to get the name of a number from the number.

E.g.

print(:GetNameFromNumber(20))
Twenty

#2

No. You’ll have to make one yourself, or find one online.

2 Likes
#3

I wrote one last year Number reader function

(if you can't access that post)

I wrote a function that takes a number input and reads it out in words. It works for all nonnegative integers up to 10^3006 - 1

function read(n)
	n = tostring(n or ""):match("^0*(.*)$")
	if #n == 0 then return "zero" end
	if #n > 3 then
		local x = {"thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion", "septillion", "octillion", "nonillion"}
		local y = {"", "un", "duo", "tre", "quattuor", "quin", "sex", "septen", "octo", "novem"}
		local z = {"t", "dec", "vigint", "trigint", "quadragint", "quinquagint", "sexagint", "septuagint", "octogint", "nonagint"}
		for i = 2, #z do
			for j = 1, #y do
				x[#x+1] = y[j]..z[i].."illion"
			end
		end
		y[3], y[10] = "do", "ovem"
		local v = {"cen", "ducen", "trecen", "quadringen", "quingen", "sescen", "septingen", "optingen", "nongen"}
		for h = 1, #v do
			for i = 1, #z do
				for j = 1, #y do
					x[#x+1] = v[h]..y[j]..z[i].."illion"
				end
			end
		end
		x[#x+1] = "millillion"
		local c = (#n - 1)%3 + 1
		local remain = n:sub(c+1)
		return read(n:sub(1, c)).." "..x[math.ceil(#n/3)-1]..(remain:find("[^0]") and " "..read(remain) or "")
	end
	local a = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}
	local b = {"", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"}
	local c = {[0] = "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}
	if #n == 1 then
		return a[tonumber(n)]
	elseif #n == 2 then
		local ones = tonumber(n:sub(2, 2))
		local tens = tonumber(n:sub(1, 1))
		if tens == 1 then
			return c[ones]
		elseif ones == 0 then
			return b[tens]
		else
			return b[tens].." "..a[ones]
		end
	elseif #n == 3 then
		local rest = read(n:sub(2))
		return a[tonumber(n:sub(1, 1))].." hundred"..(rest == "zero" and "" or " "..rest)
	end
end

e.g. print(read("133790018675309123456789042"))

one hundred thirty three septillion seven hundred ninety sextillion eighteen quintillion six hundred seventy five quadrillion three hundred nine trillion one hundred twenty three billion four hundred fifty six million seven hundred eighty nine thousand forty two

5 Likes
#4

Awesome thanks