Hello! How can I get the highest number from a table? The table below would be an example.
local test = { 1, 2, 3, 10, 321 }
Hello! How can I get the highest number from a table? The table below would be an example.
local test = { 1, 2, 3, 10, 321 }
local greatestNumber = 0
for _, number in ipairs(tableHere) do
if number > greatestNumber then
greatestNumber = number
end
end
Thanks!
30 limit lol sorry
If it’s just an array then there’s math.max, no need to loop. math.max will return the maximum value among the numbers its given, so you can just unpack the table into math.max.
local test = {1, 2, 3, 10, 321}
local highestNumber = math.max(table.unpack(test))
print(highestNumber) --> 321
besides what Colbert suggested, another option is using table.sort()
local test = {1, 10, 321, 2, 3}
table.sort(test)
local highestNumber = test[#test]
print(highestNumber) --> 321
no need for any loops at all really
but that mutates the table. What if you want to preserve the table in its original order?
I said it was another option, never said you should use it
I prefer the way colbert did it anyways, since it doesn’t mess with the table
What if you want to preserve the table in its original order?
you would have to save the previous table, I don’t know another way that would work
You could initialize greatestNumber
to -math.huge
if you want to support negatives