Help me with adding numbers?

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#21 
volume >= 0

Runs if the volume is greater than 0.

volume < 0

Will run if 0 is greater than the volume, which will never happen since the volume cannot be negative.

#22

Your not doing that though

	if (volume >= 1) then
		print(volume.." is higher or equal to 1")
		volume = 0
	elseif (volume >= 0) then
		print(volume.." is lower than 1")
		volume += 0.1
	end
``` you didn't even check if the thing thats greater than 0 is lower than 1
#23 
if (volume >= 1) then
		print(volume.." is higher or equal to 1")
		volume = 0
	elseif (volume >= 0 and < 1) then
		print(volume.." is lower than 1")
		volume += 0.1
	end
#24 
	if (math.floor(volume) >= 1) then --// Checks if the volume is greater or equal to 1
		print(volume.." is higher or equal to 1")
		volume = 0
	elseif (math.floor(volume) >= 0) then --// If its not greater or equal to 1, it will then check if it's greater than 0.
		print(volume.." is lower than 1")
		volume += 0.1
	end

Theres no point to check if its lower than 1 since it’s obviously lower than one since the first compare returned as false

#25

Oh yeah thats true idk whats wrong then

1 Like
#26

There are plenty of ways to approach this sort of method. You could store the volume somewhere in an IntValue, use n = n - (n % 1) to get rid of any loose decimal numbers each time you change the volume, or take a different approach with your conditional statements.

I personally think @JarodOfOrbiter has the best approach:

This is not only the easiest method to understand (arguably), but it’s also shorter and faster to apply than any of the methods I’ve listed above.

#27 
if (volume >= 1) then
	print(volume.." is higher or equal to 1")
	volume = 0
else
	print(volume.." is lower than 1")
	volume += 0.1
end