Yes you can.
If you don’t want to destroy the part Change:
v:Destroy()
To:
print(v.Name)
Yes you can.
If you don’t want to destroy the part Change:
v:Destroy()
To:
print(v.Name)
Yes, I understand, but I want it so you can see if multiple parts are the closest instead of one. I have 50 parts in workspace and I want to see which ones are the 2 closest.
I have already told you that you can print multiple parts that are closest to the humanoid root part character.
k found out how
local PartsToFind = 3
game.Players.PlayerAdded:Connect(
function(player)
player.CharacterAdded:Connect(
function(Character)
local humanoidRootPart = Character:FindFirstChild("HumanoidRootPart")
local dictionary = {}
for i, v in pairs(workspace:GetChildren()) do
if v:IsA("Part") and string.sub(v.Name, 1, 4) == "Part" then
dictionary[v.Name] = (humanoidRootPart.Position - v.Position).Magnitude
end
end
wait(3)
local array = {}
for _, value in pairs(dictionary) do
table.insert(array, tonumber(value))
end
table.sort(array)
for i = 1, PartsToFind do
local key = array[i]
for i, v in pairs(dictionary) do
print("Is " .. key .. " equivalent to " .. v)
if v == key then
workspace[i].BrickColor = BrickColor.new("Pink")
end
end
end
end
)
end
)