How come, this table doesn't print out in order?

[matt1020304050]

local hairButtons = {
	hair1 = hairScrollingFrame:WaitForChild('ViewportFrame1'),
	hair2 = hairScrollingFrame:WaitForChild('ViewportFrame2'),
	hair3 = hairScrollingFrame:WaitForChild('ViewportFrame3'),
	hair4 = hairScrollingFrame:WaitForChild('ViewportFrame4'),
	hair5 = hairScrollingFrame:WaitForChild('ViewportFrame5'),
	hair6 = hairScrollingFrame:WaitForChild('ViewportFrame6')
}

for key, button in pairs(hairButtons) do
	print("Key:", key, "Button:", button)
end

Output:

13:44:11.373 Key: hair5 Button: ViewportFrame5 - Client - LocalScript:32
13:44:11.374 Key: hair4 Button: ViewportFrame4 - Client - LocalScript:32
13:44:11.376 Key: hair2 Button: ViewportFrame2 - Client - LocalScript:32
13:44:11.376 Key: hair1 Button: ViewportFrame1 - Client - LocalScript:32
13:44:11.377 Key: hair3 Button: ViewportFrame3 - Client - LocalScript:32
13:44:11.378 Key: hair6 Button: ViewportFrame6 - Client - LocalScript:32

[Katrist]

Dictionaries don’t print in order. Only arrays do.

[matt1020304050]

How can I sort this? /////////////////

[txcIove]

Just make it an array and use hairButtons[1] to index them.

[Katrist]

You can’t. Just use an array like @txcIove said.

Code:

local hairButtons = {
	hairScrollingFrame:WaitForChild('ViewportFrame1'),
	hairScrollingFrame:WaitForChild('ViewportFrame2'),
	hairScrollingFrame:WaitForChild('ViewportFrame3'),
	hairScrollingFrame:WaitForChild('ViewportFrame4'),
	hairScrollingFrame:WaitForChild('ViewportFrame5'),
	hairScrollingFrame:WaitForChild('ViewportFrame6')
}

for i, button in ipairs(hairButtons) do
	print("Key:", "hair".. i, "Button:", button)
end

[matt1020304050]

I need to identify each index later though. Rip I’ll just add numbers to their names and do a search.

[Nekoshirowa (Shiro Wa)]

or why not just setting the index like [“hair1”] and so on then using:

How would you sort a table in Alphabetical Order?

You can actually just call :lower() or string.lower() on the variable (a) and (b) to compare them with their ASCII values. I tested it myself and it worked. table.sort(tbl, function(a,b) return a:lower() < b:lower() end) for i,v in pairs(tbl) do print(v) end Output: a, B, c

on the index

[Katrist]

That only works on arrays. You won’t be able to sort indices.