How to Check for a Specific Item in a Table?

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#1

In my table, I got a few Fruits that are already part of the table. Now I want to add another Fruit to the table, I would need to check if that Fruit Exist in the table or not. If the Fruit does not Exist in the table then I would add it in.

In my script, It’s checking for all the Fruits, but sense 3 of the items do not equal the ItemName its adding Orange in 3 times. How do I Make it add only once?

local ItemName = "Orange"

Table = {"Apple","Pear","Bannana"}

for i,v in pairs(Table) do
    if v.Name ~= ItemName then
        table.insert(Table,ItemName)
    end
end
#2 
for i = 1, #Table do
   if Table["Apple"] == nil then
      Table["Apple"] = "Name"
       
   end
end
1 Like
#3 
local ItemName = "Orange"

Table = {"Apple","Pear","Bannana"}

local function exists(value)
	for i,v in pairs(Table)do
		if v == value then return v end
	end
end

local function addElement(name)
	if not exists(name) then
		table.insert(Table,name)
		print("adding")
	else
		warn(name .. " exists in table")
	end
end

addElement("Strawberry")

for i,v in pairs(Table)do
	print(i,v)
end
1 Like
#4

Thanks! :slight_smile: This really helps!!

1 Like
#5

Too much work just for verifying a value in an array.

local item = "Pear"
local t = {"Apple","Pear","Banana"}

local index = table.find(t, item)
if index then print("Item exists")
   return t[index]
end
-- and to shorten the other one

if not table.find(t, item) then t[#t+1] = item end

@ffancyaxax12 Your code is almost correct:

local ItemName = "Orange"

Table = {"Apple","Pear","Bannana"}

for _,v in ipairs(Table) do
    if v ~= ItemName then -- the v here is the corresponding value for the associated index that the placeholder variable '_' will hold on each iteration, it's not an object that has a 'Name' property or 'Name' element either.
        table.insert(Table, ItemName)
    end
end

In your code, just removing the Name part from v.Name and just changing it to v should seal the deal, ipairs is just canonical for arrays.

5 Likes
Know if the index exist?
#6

I have to give you the solution its much shorter and efficient. Thanks!

1 Like