How to check if player has successfully loaded?

Help and Feedback Scripting Support
31

Sorry, I assumed you only wanted the menu to appear once and not after the player dies as well.
If you want the menu to appear on screen after the player respawns, you could try replacing ResetOnSpawn with simply checking when the button is pressed.

local Menu = player.PlayerGui:WaitForChild("Menu", 5)
if Menu ~= nil then -- Make sure the UI exists
    --Disable the character scripts
	for i, v in character:GetDescendants() do
		if not v:IsA("Script") or not v:IsA("LocalScript") then continue end
		v.Enabled = false
	end
    
    --Check for whenever the play button is pressed
    local PlayerLeaveConnect
    local ButtonConnect
    ButtonConnect = Menu.Path.To.Button.MouseButton1Down:Connect(function()
        --Finally, enable the character scripts when the player presses the play button.
		for i, v in character:GetDescendants() do
			if not v:IsA("Script") or not v:IsA("LocalScript") then continue end
			v.Enabled = true
		end
        --Prevent memory leaks
        ButtonConnect:Disconnect()
        ButtonConnect = nil
        if PlayerLeaveConnect ~= nil then
            PlayerLeaveConnect:Disconnect()
            PlayerLeaveConnect = nil
        end
    end)

    PlayerLeaveConnect = player.Destroying:Connect(function()
        --Prevent memory leaks
        if ButtonConnect ~= nil then
            ButtonConnect:Disconnect()
            ButtonConnect = nil
        end
        PlayerLeaveConnect:Disconnect()
        PlayerLeaveConnect = nil
    end)
else
    --warn("Missing UI!")
end

Remember to change “Menu.Path.To.Button” to be correctly where your button is in the menu

And then remove the script connecting the play button to turning the UI’s ResetOnSpawn off. This way, the UI will still show because ResetOnSpawn is true, but we’ll be able to tell if the play button was pressed.

Would’ve posted this kind of solution a while ago but I was tired when writing my original solution.
This should work.