I don’t know if this is against the rules or not but, guys I need ideas for me to script. Or atleast challenges, got any ideas?
If you’re a little advanced at scripting, I recommend you check out this series (only the first part out as of now):
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Thanks, Luckily I know a bit of French but only enough to go up to probably 20.
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hackerrank.com is a fun place to kill some time with programming challenges, and it can also help with practicing for the kinds of quizzes you see in job interviews.
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A few months ago I was bored and tried a simple chalenge you might enjoy as well.
Could you build a cube (6 bricks as faces) in Roblox with just a for loop? You can only insert a block per iteration. No if statements. Just set the parts’ Position (or CFrame) and Size.
for i = 1, 6 do
...
end
gl, hf!
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Can I initialize variables outside the for-loop?
Of course, but only for the sake of efficiency/readability. For example, declaring local part = Instance.new("Part"), or local side = 3 --studs.
What I mean is that Vector3 (or CFrame) values cannot be previously defined:
local pos = {Vector3.new(0, 0, 5), Vector3.new(0, 0, -5), etc.} -- cheater!! >:o
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I’ll assume ternary operations aren’t allowed either, since they’re similar to if statements?
Like: local xAngle = (i > 4) and 0 or (i * math.pi / 2)
Hmm… I didn’t think about it… but why not? It was intended mainly for math operators and that stuff, but solving it as you suggested would be a bit challenging too. 
@AskWisp I guess you couldn’t think of anything harder… especially for the 6th challenge! 
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Here’s my cube script.
-- input declarations
local width = 4
local baseCF = CFrame.new(0, 10, 0)
local size = Vector3.new(width, 0.1, width)
local ninety = math.pi / 2
-- inner loop variables
local x, z, part
-- position them with X and Z coords
-- front: x = 90, z = 0 i = 1
-- top: x = 180, z = 0 i = 2
-- back: x = 270, z = 0 i = 3
-- bottom: x = 360, z = 0 i = 4
-- left: x = 0, z = 90 i = 5
-- right: x = 0, z = -90 i = 6
for i = 1, 6 do
x = (i > 4) and 0 or (i * ninety)
z = (i < 5) and 0 or (((-1) ^ i) * ninety)
part = Instance.new("Part")
part.Name = i
part.Anchored = true
part.Size = size
part.CFrame = baseCF * CFrame.Angles(x, 0, z) * CFrame.new(0, width / -2, 0)
part.Parent = workspace
end
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Cube.
code
local w = 5
local o = CFrame.new()
local s = Vector3.new(w, 0.05, w)
for i = 1, 6 do
local x = (math.min(i-1, 4)%4)*math.pi/2
local z = (2^(math.max(i, 4)-4)-1)*math.pi/2
local p = Instance.new("Part")
p.Anchored = true
p.CFrame = o * CFrame.Angles(x, 0, z) * CFrame.new(0, w/2-s.Y/2, 0)
p.Name = i
p.Size = s
p.Parent = workspace
end
what have I done
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Beautiful!
My solution (it can hurt your eyes though):
local WorldPosition = Vector3.new()
local Side = 10
local Sample = Instance.new("Part")
Sample.Anchored = true
for i = 1, 6 do
local Part = Sample:Clone()
Part.Size = Vector3.new(Side * math.abs(1 - math.floor(1.5 - 0.2 * i)), Side * math.abs(1 - math.floor(0.2 * i)), Side * math.abs(1 - (1 - math.abs(math.floor(0.5 * i - 1.4)))))
Part.Position = WorldPosition + Vector3.new((-1)^i * Side/2 * math.floor(1.5 - 0.2 * i), (-1)^i * Side/2 * math.floor(0.2 * i), (-1)^i * Side/2 * (1 - math.abs(math.floor(0.5 * i - 1.4))))
Part.Parent = workspace
end
(This is totally not generalizable and totally not elegant.)
1 Like
Cube, again. Without using math.
code²
local w = 5
local o = CFrame.new()
local s = Vector3.new(w, 0.05, w)
local pihalfs = 1.5707963267948966
for i = 1, 6 do
local x = (((i-1)/4)%1)*4*pihalfs
local z = 2^(i-5)-(2^(i-5))%1
z = z-z%1
z = (z+(z/2)-(z/2)%1)*pihalfs
local p = Instance.new("Part")
p.Anchored = true
p.CFrame = o * CFrame.Angles(x, 0, z) * CFrame.new(0, w/2-s.Y/2, 0)
p.Name = i
p.Size = s
p.Parent = workspace
end
why is this even possible
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How do you even come up with this? God, my knowledge of mathematics is just… nothing… 
1 Like
Here’s my code :
cubePosition = Vector3.yAxis * 10
cubeSize = Vector3.one * 10
for i = 1, 6 do
local vectorTable = {1, 0, 0, 0}
for _ = 1, i - 1 do
local vectorTable2 = {0, 0, 0}
for i2 = 1, 3 do
vectorTable2[i2] = math.max(vectorTable2[i2] * 2 - 1, -vectorTable[i2])
vectorTable2[i2 + 1] = math.max(0, -vectorTable[i2])
end
vectorTable = vectorTable2
end
for i2 = 1, 3 do
vectorTable[i2] = math.abs(vectorTable[i2] - (vectorTable[i2 + 1])) * vectorTable[i2]
end
local sizeVectorTable = {}
for i2 = 1, 3 do
sizeVectorTable[i2] = 1 - math.abs(vectorTable[i2])
end
local part = Instance.new("Part")
part.Anchored = true
part.Position = cubePosition + Vector3.new(unpack(vectorTable)) * cubeSize / 2
part.Size = cubeSize * Vector3.new(unpack(sizeVectorTable))
part.Parent = workspace
end
1 Like