Weird if / then statement conditions

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#1

I want to shorten the if / then statement once again by removing unnecessary object.Name =='s but it becomes weird

Checks every condition:

local object = script.Parent
if object.Name == "name1" or object.Name == "name2" or object.Name == "name3" then
	print("Hello World!")
end

If the object name is name1, name2 or name3 it will print Hello World!
---
Checks only the first condition:

local object = script.Parent
if object.Name == ("name1" or "name2" or "name3") then
	print("Hello World!")
end

If the object name is name1 it will print Hello World! but if the name is name2 or name3 it will do nothing
---
Checks only the second condition:

local object = script.Parent
if object.Name == ("name1" and "name2" or "name3") then
	print("Hello World!")
end

It will print if its name is name2
---
Checks only the third condition:

local object = script.Parent
if object.Name == ("name1" and "name2" and "name3") then
	print("Hello World!")
end

Now, it prints Hello World! only when the object name is name3

I guess it checks the latest and else the first or

So how do I keep them normal without repeating object.Name ==?

#2

So you want it when an object is named name 1 2 and 3 it says hello world

#3

If I understood you correctly -

Using Ternary might be helpful here.

Ternary[link 2] can be very helpful to shorten if statements.

1 Like
#5

just do a for loop which loops with the names.
example:

local PossibleNames = {"name1","name2","name3"}
local ObjectName = script.Parent.Name

for _,v in pairs(PossibleNames) do
if ObjectName == v then
print("hello world")
end
end

I hope I was helpful.

1 Like
#6 
local object = script.Parent
local names = {"name1", "name2", "name3"}
if table.find(names, object.Name) then print("Hello world!") end

A table is the right idea, table.find() can be used if you want to shorten the code even further.

1 Like
#7

Ik I’m kind of late but If you want it to have name1 only be the one to say hello world then you would have to set an elseif statement