B_rnz
(B_rnz)
#1
How would I go about getting another array inside of an array without having to need a variable for it?
For example:
Knives = { {} --[[ Legendary ]] , {} --[[ Rare]] , {} --[[ Uncommon ]] , {} --[[ Common]] }
How would I go about accessing each array, without having to add
Knives = {-- Legendary = {}, }
?
The ‘variables’ are called keys, and keys always exist, even if they are numeric.
You can use this to read from your first example.
legendary = Knives[1]
uncommon = Knives[3]
B_rnz
(B_rnz)
#3
Usually if I had keys, all I would have to do is…
Playerdata[Player]["Knives"]["Legendary"]
But i’m not trying to do this so…
for i, v in pairs(PlayerData) do
Playerdata[Player]["Knives"][v[1]] -- First array in 'Knives' table
end
Would this even work, i’m not in studio right now.
I am assuming that Playerdata[Player].Knives is the Knives table?
for i, v in pairs(Playerdata[Player]["Knives"]) do
-- v = legendary table, uncommon table, etc
end
B_rnz
(B_rnz)
#5
Yes, I see.
So basically I wouldn’t need to Search through playerdata I could already have that inside pairs, it could be a simplistic way of doing things.
So all I need to do is,
for i, v in pairs(Playerdata[Player]["Knives"]) do
print(v[1], v[2], v[3], v[4]) --Prints each array sorted from legendary to common
end
to get each knife string inside the array, correct?
Nevermind, used LuaDemo to test, and this works.
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