So explanation is
I have a string it says
10/10/10+10
ok?
now normally using loadstring the answer would be 10.1 but as loadstring is dangerous I want to use string.split and gsub and sub and idk what more to do that
I want a system to sperate the first 3 tens leaving the last one with the + so
10/10/10+10
after fraction
0.1+10
after addition
10.1
How would I achieve such wizardry?
pls help me D;
Won’t that do that automatically for you?
10/10/10 = 0.1,
0.1 + 10 = 10.1
If it’s a string, can’t you just use patterns [%d] to switch them into numbers and get the result?
[or maybe using tonumber could help]
nope that wont do automatically that would if i used loadstring which i dont want to cause exploiters and stuff
why dont just use:
local stringg = 10/10/10 + 10
local tostringg = tostring(stringg)
So, I’d say to get the right area of the 10’s string by doing
local fraction = string:sub("10/10/10+10", 1, 9) -- take note, an empty space `""` counts as a character, so you're always starting with 1
then afterwards, now what you can do is separate that fraction string by getting “/”, then afterwards making a math function manually:
local tens = fraction:split("/") -- This will make a table of all of the values that was "splitted".
local theNewFraction = tonumber(tens[1]) / tonumber(tens[2]) / tonumber(tens[3]) + tonumber(string:split("10/10/10+10", 9)) -- This is just using that table and making it into an actual math function.
Using it in an actual code, it should look something like this:
local fraction = string:sub("10/10/10+10", 1, 9)
local tens = fraction:split("/")
local theNewFraction = tonumber(tens[1]) / tonumber(tens[2]) / tonumber(tens[3]) + tonumber(string:split("10/10/10+10", 9))
print(tostring(theNewFraction))A very complicated way of doing the math with a string, but it should work. Let me know what type of problems you encounter using this.
so @edozune and @Super_pro322222 i am sorry to say but both of these methods are not what I want you see I am making a calculator! and it shouldnt use loadstring cause its bad backdoors and stuff anyways the equation is not always 10/10/10+10 it can be different most of the times
so if you’re making a calculator then just replace 10/10/10 with input1/input2/input3 + input4
inputs should be tonumber(string)
i think you still dont get it
so another example
lets say a player inputted 10+10-10
now if i do string.split(“10+10-10”,"+") it would return {“10 10-10”} see thats the problem
roblox would just error unless… wait a second HOLD UP
This isn’t something that can be done easily. You will need to learn to write a parser, and it’s not something that can be done in an afternoon. Do a search for arithmetic parser.
yea i know its complex as hell but rn i am trying to make a simpler one using tables ill make sure to keep all of you updated!
well I made this and it sucks at math more than a 3rd grader
local subtab = {}
local addtab = {}
local function solve(input)
local sub = string.split(input,"-")
for i,v in pairs(sub) do
if not string.find(v,"+") then
table.insert(subtab,v)
else
local add = string.split(v,"+")
for _,a in pairs(add) do
table.insert(addtab,a)
end
end
end
local num = 0
for _,a in pairs(addtab) do
num += a
end
for _,s in pairs(subtab) do
num -= s
end
print(num)
end
solve("5-10-10")
well it works now
local r = loadstring("5-10-10")
r()
yup it surely does
What if you’ve actually gotten the numbers and operations as strings?
Like, make a table for all possible number and operation values:
numbers = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
operations = {"+", "-", "*", "/", "^", "%", "sqr", "log"}
Then make it so that it’ll find if the string has any of that in there, it’ll find the first and add it onto an expressed equation. Just an idea.
that is a fine idea and would try that in the future but rn ama stick to da 2 lines of code that makes everything work : ) (yea i gave up)
I’ll try to do this on my own research, would it be okay to PM you when I found a solution? Maybe you can use it for your calculator.
yea sure i dont see why not! and its not like necessary for you to do search you know?
Yeah, but you wanted to do it without using a loadstring and I know it’s possible. So, I just wanted to kind of fulfill the initial request, which was doing it without the loadstring.
hmm that is right and thank you very much!
@Qinrir, JUST FOUND A WAY TO DO IT WITHOUT LOADSTRING.
So, using a module called: Luaxp, it can help with making a string a mathmatical function, and it’ll automatically return as a string back.
Put the module in ReplicatedStorage and put this code inside of your script, modify it to add more conditions and valla!
local parser = require(game.ReplicatedStorage:WaitForChild("MainModule"))
local expression
TextBox = script.Parent.TextBox
if TextBox then
for buttons, button in ipairs(script.Parent:GetChildren()) do
if button:IsA("TextButton") then
if button.Name == "=" then
button.MouseButton1Click:Connect(function()
expression = parser.evaluate(TextBox.Text)
wait()
TextBox.Text = expression
end)
elseif button.Name == "C" then
button.MouseButton1Click:Connect(function()
TextBox.Text = ""
end)
elseif button.Name == "CE" then
button.MouseButton1Click:Connect(function()
TextBox.Text = TextBox.Text:gsub(".?$","")
end)
-- Going to assume you have more buttons like ^, sqr, log, etc. Like how the if statements are set up, make the button name be the symbol, and then put the symbol in as a text.
else
button.MouseButton1Click:Connect(function()
TextBox.Text ..= button.Text
end)
end
end
end
end