# Check if "20.4" is in variable

hello I need help with my code, I am trying to make an if statment

``````times = ["1.94, 9.3, 3.4, 20.4"]
if tostring(9.3) in times then --thats where I got an error (incomplete statement: expected assignment or a function call)

end
``````

I’m assuming you came from python

you can’t add “in” in an if statement in lua only “and” and “or”
and you don’t use “[]” for tables you suppose to use “{}”

``````times = {1.94, 9.3, 3.4, 20.4}
for i, v in pairs(times)do
if v == 9.3 then
print("Number found")
end
end
``````

this will check if there is a specific number in the table

Luau actually has a built-in function for finding values in a table.

``````times = {1.94, 9.3, 3.4, 20.4} -- value type 'number'

if table.find(times, 9.3) then
print("Found")
end
``````
``````table.find(tbl: table, value: any): number?
--> found something? return index
``````
3 Likes

does this work in also strings

Yes, it does, but the types have to match.

For instance, `numberAsString` is a string, but we look for it in the `times` table as a number - converted with `tonumber()`. The original `numberAsString` is still a string, because `tonumber()` returns a variable of new type, and it’s returned into `table.find()`.

``````--!strict
local numberAsString: string = "9.3"
local times: {number} = {1.94, 9.3, 3.4, 20.4}

if table.find(times, tonumber(numberAsString):: number) then
print("Found")
end
``````

On the contrary, looking for “9.3” in the table without converting would not work.