The title is really all I need to say. How would I get the name of a variable?
local nameIWantToGet = '<-- that!'
And, would the method you propose work with table variables?
local tableWithNames = {
nameIWantToGet = '<-- that!',
}
The title is really all I need to say. How would I get the name of a variable?
local nameIWantToGet = '<-- that!'
And, would the method you propose work with table variables?
local tableWithNames = {
nameIWantToGet = '<-- that!',
}
I am slightly confused about what the use case of this would be. If you didn’t already know the name of a variable, why are you trying to access it?
you cant unless its a string or number i think
local tableWithNames = {
"nameIWantToGet" = "whatever",
}
for i, v in next, tableWithNames do
print(i)
end
That’s the thing, the script wouldn’t be able to get a string version of the name of that variable.
This WILL work if you surround “nameIWantToGet” in brackets, but I’ve seen other scripts get the name without that. I would love to do it with the normal way (without brackets and strings).
It’s impossible to change the name of a variable or get the name of a variable in Lua, the language Roblox uses. There are no keywords for this. While running, the script actually doesn’t even care what the variables are named. It just has the keep them separate from each other and remember which is which.
I do not want to change it- I want to get the name of it as a string.
Then why would this work?
print(tableWithNames.nameIWantToGet) --> "<-- that!"
Nevermind, figured it out.
local Table = {
Food = "Apple";
}
for i, v in pairs(Table) do
print(i, v) --> "Food Apple"
end
oh now i know what you mean
you want to get the name of the variable here:
local hi = "hello"
not
local hi = {hi = hello}
Ohhhhhhhh…
That’s not a variable though. That is just the key to that object in the dictionary. Yes, that is very possible.
That’s different from a variable
Well, it works for my second use case (which I was planning to use anyways), so I’m good with it.
Fun fact: you can get the name of a variable with getfenv
, but not local variables
N1_G = 'hey'
N3_G = 'nope'
local NoShow = 20
local env = getfenv()
for k, v in pairs(env) do
if v == "nope" then
warn(k)
end
end
print(env)
As you can see there, NoShow
does not appear in the list.
Roblox uses Luau : (
Lua is a different language, the difference between the 2 is Luau is a bit more closed PC wise, while like any other language Lua can have full file access.
luau is a fork of lua, not a different language
not saying it is different as an entirely different language, im saying it is different as in what it is used for
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