Help setting player rank based on stats

Help and Feedback Scripting Support
#1 
local Players = game.Players
local PlayerInfoUI = script.PlayerInfoUI
local ClassT ={
	[10^3] = "Average Class",
	[10^4] = "Decent Class",
	[10^5] = "Middle Class",
	[10^6] = "Rich Class",
	[10^7] = "Luxurious Class",
	[10^8] = "Governer Class",
	[10^9] = "Presidential Class"
}
local RankT ={
	[1] = "Newbie Rank",
	[10] = "Decent Rank",
	[50] = "Pro Rank",
	[75] = "Fighter Rank",
	[100] = "Old Player Rank"
}

Players.PlayerAdded:Connect(function(player)
	local Level,Money = player:WaitForChild("Level"),player:WaitForChild("Money")
	local Char = player.Character or player.CharacterAdded:Wait()
	local NC = BrickColor.new(player:WaitForChild("NameColor").Value)
	local C = PlayerInfoUI:Clone()
	C.Parent = Char:WaitForChild("Head")
	C.PName.Text = player.DisplayName.."(@"..player.Name..")"
	C.PName.TextColor3 = NC.Color
	while player do
		local Rank
		for i,v in pairs(RankT) do
			if i <= Level.Value then
				Rank = v
			end
		end
		print(Rank,Level.Value)
		C.Rank.Text = Rank
		wait()
	end
end)

Ok so I want my code to set a players rank from 1 of the 5 ranks in RankT and I am suffering doing that.
Example:

Lets say the players level is 1 his/her rank is Newbie Rank Now lets say the players rank is 5 his/her rank SHOULD BE Newbie Rank NOW lets say that the players rank is 11 or 12 or 49 I want his/her rank to be Decent Rank

I hope that explains

#2

Hello,

Your dictionary seems to be incorrectly written.
Please refer to the tables documentation page:

#3

how come is it incorrectly written? can you clarify a bit?

#4

When you create a table, the index would be a number by default, because it is considered the numerical position of the value in the table.

local testDictionary = {
	FruitName = "Lemon",
	FruitColor = "Yellow",
	Sour = true

print(testDictionary[1])

--[[
Console:

Lemon
]]--
}

So when you call a for loop method on a table, it will cycle through the index as a number because the index is a numerical position, AKA a key in the table. For loops cycle through a certain amount of iterations for the code block.

For example, this table has 2 indexes and will print out the 2 index keys and values in order.

for i,v in pairs(testDictionary) do 
    print(i, v)
end

--[[ 
Console:
FruitName Lemon
FruitColor Yellow
]]--

However, for a dictionary, you can assign the index as a string variable and it will keep the same key.

When you assign a number to the index’s key, you are defining the index as the value, and the value of the index as a key. Essentially, the value and index are incorrectly labeled.

#5

hmmmmmmmm I see and I know just what to do thanks for the help

#6 
local testDictionary = {
	FruitName = "Lemon",
	FruitColor = "Yellow",
	Sour = true
}

print(testDictionary[1]) --nil

Dictionaries aren’t indexed with sequential numbers one through number of items/entries in the table, they use custom keys/fields and as such the table needs to be indexed with those keys/fields in order to access/fetch/retrieve the values assigned/associated to them.