Help With AssemblyLinearVelocity

[WindyTundra]

I have a script and i want to be able to get a parts height then translate it into the assemblylinearvelocity that is needed to get up that part.

hopefully i explained this okay.

local prompt = false
local RunningPlayers = {}

game.Players.PlayerAdded:Connect(function(plr)
	plr.CharacterAdded:Connect(function(char)
		local humanoid = char:WaitForChild("Humanoid")
		humanoid.Running:Connect(function(speed)
			if speed > 0 then -- Ensure the player is actually running
				if RunningPlayers[plr.UserId] then return end
				RunningPlayers[plr.UserId] = true

				local humRoot = char:WaitForChild("HumanoidRootPart")
				local module = require(script.Parent.ParkourCheck)
				local value, face = module.CheckPart(game.Workspace.Part, humRoot)
				
				task.wait(1)

				if value == true then
					plr.PlayerGui.ClimbPrompt.Enabled = true
				end

				if value == true and RunningPlayers[plr.UserId] == true then
					prompt = true
					print("Player is in the area")
					plr.PlayerGui.ClimbPrompt.Enabled = true
					humRoot.AssemblyLinearVelocity = Vector3.new(0,?,0)
				else
					prompt = false
					print("Player is not in the area")
					print(face)
					plr.PlayerGui.ClimbPrompt.Enabled = false
				end

				-- Reset debounce after the logic completes
				RunningPlayers[plr.UserId] = false
			end
		end)
	end)
end)

[MysteryX2076 (DrMystery)]

You can get the minimum y-val for the AssemblyLinearVelocity by getting the y-value of the part’s size, which can be smth like Size : 8,1,2. But you prob need to add the AssemblyMass of the character too since the character has mass.

In Summary:
The AssemblyLinearVelocity of the HumanoidRootPart needed can be attained by adding the part’s size’s Y-Value, the AssemblyMass of the entire character and some small change.

[greenboo5]

You can calculate how much Y-force is needed to reach a certain height with this equation:

local jumpForce = math.sqrt(2 * workspace.Gravity * JUMP_HEIGHT)

You just need to determine the jump height needed based on the part’s and player’s current positions.

[WindyTundra]

wow! that worked, could you explain why i would have to square root it though?

[greenboo5]

MATH JUMPSCARE

First we need to know some equations for projectile motion:
Vertical position by time → 0.5gt² + v't
Vertical speed by time → v'+ gt

First, we need to know at what time does a projectile reach the apex of it’s motion. Or in other words, when our speed equation equals zero:
v' + gt = 0 which solves to t = -v'/g

Next, we solve for the height of the motion, because we just solved what time we reach the apex of our jump we can plug that into our position equation:
H = 0.5g(-v'/g)² + v'(-v'/g) which solves to H = 0.5v'²/g

Lastly we can rearrange the formula to solve for the initial velocity!
v'² = 2Hg → v' = sqrt(2Hg)

Hopefully I explained it well, I just summarized this article which you can check out for a more in-depth answer if you’d like!

[MysteryX2076 (DrMystery)]

I’m good at additional math and I do not what the ducks in going on

[WindyTundra]

got it figured out, thanks for the help!