Help with elseif timer

[TheRealSpriteMan1337 (Sprite)]

Hello, devs!

I made a dynamic timer that counts up, and after certain points in time, the timer’s text is updated.

As well as being a nightmare to debug, this code runs horribly and inefficiently due to all the elseif statements. I was wondering if there was a more efficient way to do this, one that isn’t an eyesore.

Prepare yourselves mentally:

local function renderSplash()
	if ransplash == splashes[10] then
		while wait() do
			if math.round(time()) < 59 then
				splash.Text = "You've been here for "..math.round(time()).." seconds!"
			elseif math.round(time()) <= 119 then
				splash.Text = "You've been here for ".. math.round(time()) / 60 .." minute!"
			elseif math.round(time()) >= 120 then
				splash.Text = "You've been here for ".. math.round(time()) / 60 .." minutes!"
			elseif math.round(time()) >= 3599 then
				splash.Text = "You've been here for a really long time!"
			end
		end
	else
		splash.Text = ransplash
	end
end

Is there a way to do this more efficiently? How should I make this better?

[DougSwagington (RealLifeLobster)]

you could look into using math to figure out hours, minutes, seconds with modulos and use string formating to condense it without having multiple if statements like you have there

[TheRealSpriteMan1337 (Sprite)]

How would I use string formatting in this situation anyways? And math too?

[happya_x (Happya)]

you can use the os library for this

os.date() returns a dictionary with the time broken down into units and you can loop through them to generate a message

local startTime = os.time()

while task.wait(1) do
	
	local timeInfo = os.date("*t", os.time() - startTime)
	print(timeInfo)

end

--example of what os.date() returns
--[[

{
    ["day"] = 31,
    ["hour"] = 19,
    ["isdst"] = false,
    ["min"] = 8,
    ["month"] = 12,
    ["sec"] = 20,
    ["wday"] = 4,
    ["yday"] = 365,
    ["year"] = 1969
} 

[TheRealSpriteMan1337 (Sprite)]

Ah, I can use this as a base. Thanks!