Help with math.random()

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#1

Hello everyone, I was getting this error where it says “invalid argument #2 to ‘random’ (interval is empty)”. I’ll link the script down below:

local Players = game:GetService("Players")
local rand = math.random(1,3720000000)
local charAppearance = Players:GetCharacterAppearanceAsync(rand)

print("User ID: ",rand, " is a lucky person!")

If anyone has any solutions, please lemme know.

#2

I believe the second number is too big for it to calculate.

#3

Oh, how come?

I calculated larger nums like 1e308 with math.random()

#4

I’m not sure… When I tried a number with a few less 0’s it worked

#5 
local rand = math.random(1,3.72e9)

Fixed it, but doesn’t work

#6

For some reason, If we try using 372e6 it works, But 372e7 doesn’t - By knowing this, We can assume there’s a certain limit for generating random numbers using math.random. Maybe you could try using Random.new():NextInteger() instead?

-- Works
local RandomOne = math.random(1, 372e6)
print(RandomOne)

-- Errors
local RandomTwo = math.random(1, 372e7)
print(RandomTwo)
#7

I get your point, but I believe there were a much, much greater limit than 3.72e9

#8

There’s indeed a much bigger limit. I did a research and i found out that this is an “issue” with math random itself. (Can be found at this post)

As i mentioned above, You should use the Random Object instead, Since it doesn’t has this problem and also comes with some extra methods related to number-generation.

#9

I did a bit of testing, and the limit for Random:NextNumber is somewhere between 2^1023 and 2^1024, which I assume is a floating point limit thing. For Random:NextInteger, it starts returning negative values for 2^63, which I assume is an integer overflow thing.

#10

Yeah, or I can just make my own random func

#11

Yeah, so I used this line of code:

local random = Random.new(tick()):NextInteger(1,3.72e9)

And I believe it has a much higher limit.