Help with textbox and table.sort

Help and Feedback Scripting Support
#1

Any suggestions on how do i sort table accordingly to textbox text?

Currently i have this:

table.sort(pets, function(a,b)

    return a.Name == Text
    
end)

It gives: 39: invalid order function for sorting

#2

To properly use table.sort(), the sort function should return consistent results, a boolean, when a is b or b is a. Could you provide some specifics on what kind of table pets is and how you want them sorted?

#3

For example, the textbox text is cat, the table.sort function should sort table so the pet with name “cat” in the table will become on the top of it

#4

Pets = { {Name = “Dog”} , {Name = “Cat”} , {Name = “Dog”} }

it should become

Pets = { {Name = “Cat”} , {Name = “Dog”} , {Name = “Dog”} }

#5 
local function sortPetsByName(searchName: string)
	searchName = searchName:lower()
	
	table.sort(pets, function(a, b)
		if a.Name:lower():match(searchName) then
			return true
		elseif b.Name:lower():match(searchName) then
			-- return false if B matches the search name so that any matches are not pushed further down the table
			return false
		end
		
		-- normal alphabetical sort if neither A or B match the searching name
		return a.Name < b.Name
	end)
end

sortPetsByName("cat")
#6

well, it gives “invalid order function for sorting” error

#7

Did you change how the pets table is formatted?

#8

what do you mean formatted?

print(typeof(pets)) → table

#9

I used the format of the pets table that you supplied, and this works in every case

Full source:

local pets = {
	{ Name = "Dog" },
	{ Name = "Bear" },
	{ Name = "Cat" },
	{ Name = "Polar Bear" },
	{ Name = "Cat" },
	{ Name = "Peacock" }
}

local function sortPetsByName(searchName: string)
	searchName = searchName:lower()
	
	table.sort(pets, function(a, b)
		if a.Name:lower():match(searchName) then
			return true
		elseif b.Name:lower():match(searchName) then
			-- return false if B matches the search name so that any matches are not pushed further down the table
			return false
		end
		
		-- normal alphabetical sort if neither A or B match the searching name
		return a.Name < b.Name
	end)
end

sortPetsByName("cat")
#10

It works now, ty!

image
image242×513 17 KB

#11

This topic was automatically closed 14 days after the last reply. New replies are no longer allowed.