How can I determine if two arrays are equal?

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#1

Title says it all.

local a = {
	["TEST"] = {"H", "I"},
	"CAAP",
}
local b = {
	["TEST"] = {},
	"CAAP",
}

local function compare(arr1, arr2)
	for i, v in pairs(arr1) do
		if (typeof(v) == "table") then
			if (compare(arr2[i], v) == false) then
				return false
			end
		else
			if (v ~= arr2[i]) then
				return false
			end
		end
	end
	return true
end

print(compare(a, b)) --> true

The script will print out ‘true’ even though in reality it’s false. I am looking to make the compare function look deeper into the array

#2 
local a = {
	["TEST"] = {"H", "I"},
	"CAAP",
}
local b = {
	["TEST"] = {},
	"CAAP",
}

local function compare(arr1, arr2)
	if #arr1 ~= #arr2 then return false end
	for i, v in pairs(arr1) do
local a = {
	["TEST"] = {"H", "I"},
	"CAAP",
}
local b = {
	["TEST"] = {},
	"CAAP",
}

local function compare(arr1, arr2)
	if #arr1 ~= #arr2 then return false end
	for i, v in pairs(arr1) do
		if (typeof(v) == "table") then
			if (compare(arr2[i], v) == false) then
				return false
			end
		else
			if (v ~= arr2[i]) then
				return false
			end
		end
	end
	return true
end

The issue was that arr2[i] was empty, so it never iterated through anything and just returned 0. The length check fixes this.
Edit: removed debug stuff

#3

?

Screen Shot 2022-03-01 at 12.37.11 AM
Screen Shot 2022-03-01 at 12.37.11 AM2884×1482 332 KB

ㅤㅤ
ㅤㅤ

#4

You didn’t get rid of your old code.

#5

Oh okay. Thank you for the help

#6

You could also use this function

 function compare(table1, table2)
   local avoid_loops = {}
   local function recurse(t1, t2)
      -- compare value types
      if type(t1) ~= type(t2) then return false end
      -- Base case: compare simple values
      if type(t1) ~= "table" then return t1 == t2 end
      -- Now, on to tables.
      -- First, let's avoid looping forever.
      if avoid_loops[t1] then return avoid_loops[t1] == t2 end
      avoid_loops[t1] = t2
      -- Copy keys from t2
      local t2keys = {}
      local t2tablekeys = {}
      for k, _ in pairs(t2) do
         if type(k) == "table" then table.insert(t2tablekeys, k) end
         t2keys[k] = true
      end
      -- Let's iterate keys from t1
      for k1, v1 in pairs(t1) do
         local v2 = t2[k1]
         if type(k1) == "table" then
            -- if key is a table, we need to find an equivalent one.
            local ok = false
            for i, tk in ipairs(t2tablekeys) do
               if table_eq(k1, tk) and recurse(v1, t2[tk]) then
                  table.remove(t2tablekeys, i)
                  t2keys[tk] = nil
                  ok = true
                  break
               end
            end
            if not ok then return false end
         else
            -- t1 has a key which t2 doesn't have, fail.
            if v2 == nil then return false end
            t2keys[k1] = nil
            if not recurse(v1, v2) then return false end
         end
      end
      -- if t2 has a key which t1 doesn't have, fail.
      if next(t2keys) then return false end
      return true
   end
   return recurse(table1, table2)
end

then you can do

print(compare(a,b))

got it from here

1 Like