Just curious, let’s say there is a sentence, “Bob ate 5 cookies.” How can I find the number in this sentence (5), and always print the numbers regardless of their value?
More than one way, depending on your use case.
local str = "Bob ate 50 cookies"
print(string.match(str, "%d+")) --> 50 (string)
print(string.split(str, " ")[3]) --> 50 (string)
-- ...
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Option one returns the first capture of a sequence of digits, e.g. in “10 and 20” it would return “10”.
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Option two splits a string at each occurance of a whitespace. We know the number is the third string, so we read the value in the table at index 3.
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For getting all number captures, there is gmatch - which returns an interator - with the same pattern (“%d+”).
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Thanks! Do you know how to convert a value to a number?
localplr.Character.Humanoid.WalkSpeed=tonumber(string.split(msg, " ")[3])
oh wait nvm, I just used the first one and it works fine.
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