How can I make a variable for player1 and player2?

[Raven_fortnite3 (Hank)]

Title says it all.
How can I make a variable for player 1 and player 2? I want to make a 1v1 fighting game and I want to make a variable of the players.

[coolgamer294855 (slug)]

This creates a variable for player 1 and player 2, these are called Tables I believe.

player1 = {}
player2 = {}

[Rodigooz]

check this out!

-- ServerScriptService

shared.players = {}
local count = 0

game:GetService('Players').PlayerAdded:Connect(function(plr)
‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤif count > 2 then
‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤplr:Kick('Server is full')
‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤreturn
‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤend
‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤcount += 1
‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤshared.players[count] = plr
‎‎end)

to access the players only do this

players[1] -- for player 1 or 2 for player 2

[Raven_fortnite3 (Hank)]

So If I make a code of player 1 always facing at player 2, will the script understand who player 1 and player 2 is?

[Raven_fortnite3 (Hank)]

So how does this work exactly?

[coolgamer294855 (slug)]

Swift2.x

let player1 = [1: "foo", 2: "bar"]
let player2 = [1: "foo", 2: "bar"]

if player1 == player2 {
    print("player1 and player2 is equal")
}

Swift3.x

let player1 = [1: "foo", 2: "bar"]
let player2 = [1: "foo", 2: "bar"]

if player1 == player2 {
    print("player1 and player2 is equal")
}

It checks if player1 and player2 are equal.

[Rodigooz]

basically, when the players join, the server adds the player to a Dictionary Table and adds +1 to server count, if the server count is more than 2, the players that have been joined will be kicked, you can use PlayerRemoving to subtract the count variable

[Raven_fortnite3 (Hank)]

Will I be able to use a player in that dictionary table in other scripts?

[Rodigooz]

no but you can change it, check out the message again, i’ll be doing to others codes can access

[Rodigooz]

to access in other code you can do this:

shared.players[1]

[Raven_fortnite3 (Hank)]

well i got to go for now. But ill come and try whatever you send.

[Rodigooz]

ok!‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ‎‎‎‎‎‎‎‎ㅤ