How do i get the lowest number of this table?

Help and Feedback Scripting Support
#1

I have this table for example:

local tlabel = {{4,"D"},{2,"B"},{1,"A"},{3,"C"}}

How would i get the table with the lowest number of this table?

#2

You can pass a custom sort function with table.sort

local tlabel = {{4,"D"},{2,"B"},{1,"A"},{3,"C"}}

local function customSort(left, right)
	return left[1] < right[1]
end

table.sort(tlabel, customSort)
print(tlabel) -- {{1,"A"},{2,"B"},{3,"C"},{4,"D"}}
#4

One way you could go at the problem is by looping through the table, then checking to see if the current number is lower than that last one checked, and storing the lower one into a variable.

Here’s an example that I turned into a function for easier understanding:

local tlabel = {{4,"D"},{2,"B"},{1,"A"},{3,"C"}}

function findLowestValue(tbl)
	local lowestNumber = nil
	local lowestIndex = nil
	for i, data in pairs(tbl) do
		local number = data[1]
		local letter = data[2]
		if not lowestNumber or lowestNumber > number then
			lowestNumber = number
			lowestIndex = i
		end
	end
	
	return tbl[lowestIndex]
end

print(findLowestValue(tlabel)) -- returns {1,"A"}
#6

This is the correct solution, to get the table which contains the smallest value you’d just index the first item of the array named “tlabel”.

#7

Oh, i didn’t realize that, sorry for that.