How do i loop through this table

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#1

Not good with tables so

local tabled = {
	A = 2,
	B = 3,
	C = 4,
	D = 5,
	E = 6
}

Wondering how i could loop through a table like this in order
ipairs dont work and pairs just randomizes it somewhat

Any ideas on how to improve my inventory system?
#2

This is a dictionary. You could try something like this -

local List = {
	["A"] = 1,
	["B"] = 2,
	["C"] = 6,
	
}

for p, q in pairs(List) do
	print(p, q)
end

BUT if you want to print their values in order, convert it into an array :

local tabled = {
	{"C",2}, -- letter,value
	{"B",5},
	{"A",3},
}


--This will sort our table in the given order, 
--in our case, we want to return it from smallest to largest
--a[2] and b[2] are the second values in each table in our array, which is the number/value.
table.sort(tabled,function(a,b)
	return a[2] < b[2]
end)

for index,tab in ipairs(tabled) do
	print(tab2])
	--Would print 2,3,5 although it looks like in the original table it's supposed to be 2,5,3
end

Read more at :

1 Like
#3

You sadly can’t apply table.sort on dictionaries, nor on organized orders.
Only on arrays to my knowledge.

#4

local tabled = {
[“A”] = 2,
[“B”] = 3,
…and so on
}

for k, v in pairs(tabled) do
print(k, v) —A, 2, B, 3, and so on
end

I’m on mobile, sorry for no text formatting.

#5

Notice that if he wanted to print them in order [ their values], you can’t use this. ipairs won’t work in this code. So he would’ve needed to convert it into an array.

1 Like
#6

As others have said you can’t conventionally get order from a looped dictionary. You might be able to make some kind of work around if you made an array with all the keys:

{"A","B","C"}

If you looped through that it would get the ordered values and you could search for the correct values in the dictionary using each key.

1 Like
#7

im pretty sure im interpreting this wrong but something like a normal table with keys matching the dictionary and i just pull from the dictionary with the normal table?

#8

Correct, you would create a table for “the order of the keys” and then get the values by the key.

local KeysOrder = {"A", "B", "C"}
local Table = {A = 1, C = 3, B = 4}

for Index, Value in ipairs(KeysOrder) do
    print(Table[Value])
end

Output:

1
4
3
1 Like
#9

Alright i get it now, just a quick question so i dont have to make a entire new post
In one of my previous posts i was asking about a inventory system and they said to

“Simply store your frame in a table with the tool instance as the key”

Im not entire sure what to do here but heres what i think it means
Like when a child is added to the inventory create a new instance in the dictonary matching the tool as the thing and the frame as the other thing someting like

local D = {
Tool = Frame
}

-- Or

local B = {
Frame = Tool
}

And it will just add a new one one on child added event

Not sure how to add a dictonary to a table
Not sure how to check for the instance when the child is removed

#10

You’ll have to explain exactly what you’re trying to achieve.

In lua tables are dictionaries in a sense. You add a dictionary to an existing table by doing this:

local tab_ = {1,2,3}
tab_["NewValue"] = "new value"

You’re going to have to explain what you mean.

#11

basically when a child is added, it will a dictonary with the instance that got added, and a frame that was made from the instance, and when a child is removed, i want to check through the dictonary to find that instance that matches with the instances that is being removed, and remove the frame it created

Alright ill try this out

#12

You can use bracket indexing to add a tool-frame pair to the dictionary, using the tool as the key. You can then find the frame and remove the tool-frame pair using the tool instance as the key once again.

local toolFrameMap = {}

local function onChildAdded(tool)
    local frame = -- create the frame

    toolFrameMap[tool] = frame
end

local function onChildRemoved(tool)
    local frame = toolFrameMap[tool]

    -- destroy/clean up the frame

    toolFrameMap[tool] = nil
end
1 Like
#13 
local myTable = {
	{"A", 2},
	{"B", 3},
	{"C", 4},
	{"D", 5},
	{"E", 6},
}

for i, data in ipairs(myTable) do
	print(i, data[1], data[2])
end

or

local instances = {}

local function ChildAdded(child)
	local frame = Instance.new("Frame")

	instances[child] = frame
end

local function ChildRemoved(child)
	local frame = instances[child]
	frame:Destroy()
	instances[tool] = nil
end

oops i never noticed the question was already answered

#14

ayy it worked, tysm have been wondering how to do something like this for a bit :smiley: :+1: