How do I make a loop run however many times a number value is, without changing the value?

Help and Feedback Scripting Support
#1

You can write your topic however you want, but you need to answer these questions:

  1. What do you want to achieve? I want to make a loop run however many times the number value is, without changing the value.

  2. What is the issue? I have no clue what to do.

  3. What solutions have you tried so far? I looked it up multiple different ways but I couldn’t find what I was looking for.

while wait(0.5) do
	for i,plr in pairs(game.Players:GetChildren()) do
		 ammountofjump = plr.Potions.JumpPotions
		if plr.team == game.Teams.Playing then
			print("Playing")
			if ammountofjump.Value >= 1 then
				wait(1)
				local jumpclone = game.ServerStorage.Potions.JumpPotion:Clone()
				jumpclone.Parent = plr.Backpack
				ammountofjump.Value = ammountofjump.Value - 1
				end
end
end

I am making a round based game, and I made a number value that is named JumpPotions. The value of it is how many jump potions the player has. Im kinda making a inventory system. But if I add a script that saved progress, if they leave while the game is running the value will be zero and they will save with no potions. Now I need to figure out how I do what was listed in the title.

#2

have you tried adding another value and copying the new value’s value to the first value’s value, then you can change the value of the 2nd one instead?

#3

Yes, but it is a loop so the second value gets reset to the first.

#4

yes but then you can change the 2nd value to the first value again after the end of the loop
cycle

#5

but everytime it runs again it get reset to the first value so it stays at the first value and doesnt go down.

#6

you’re using a number value as the number right?

#7

Yeah im using the value of the number

#8

wait im a bit confused: are you trying to go from 0 to the first value’s value?
or: are you trying to count the amount of loops it does?
or: are you trying to loop the amount of times the first value’s value?

#10

So basically, you can buy a potion from the shop, then the value of it goes up, then it gives you that many potions that the value has once the round starts.

#11

I already tried that but the value gets reset after every loop.

#12

couldnt you just add another counter? and make the value: counter - 1 every time you use the potions and counter + 1 everytime you buy a potion?

#13

Yeah, I never thought of that, it might get a little messy though because of how many potions I have.

#15

maybe try having a limit amount of potions allowed after every round? like 2 potions every round so its not too op and solves your problem?

#17

Yes I did that, it just that there will be so many different potions.

#18

If you can customize this to your script, it does work for me

local Value = game.Workspace:FindFirstChild("Value").Value

for count = 1, Value do
	print("Looping... Goal: "..Value.." times")
end
wait()
print("Finished!")
Value = 0
#19

well, it will be messy, but you will find out how to make it simpler once you make it the first time.

#20

Mine happens literally instantly, to add delay do:

local Value = game.Workspace:FindFirstChild("Value").Value

for count = 1, Value do
	print("Looping... Goal: "..Value.." times")
    wait(1)  
end
wait()
print("Finished!")
Value = 0
#21

I will try this, if it doesnt work than I will do what the NoobDev did.

#22

This was kinda my first post, so thankyou.

#23

No problem, change it to this though. Found an error resetting it to 0

local Value = game.Workspace:FindFirstChild("Value")

for count = 1, Value.Value do
	print("Looping... Goal: "..Value.Value.." times")
	wait(1)  
end
wait()
print("Finished!")
Value.Value = 0

Basically now the variable is just the value itself, then doing .Value to get it’s value