How do I shorten this type of code

[jaminz4 (jamie)]

I’m convinced that a quicker way of writing this exists, and although the method I used does technically work fine with larger applications it becomes extremely tedious but I have always wrote each line individually. I’ve tried looking around for it but have no clue where to start or what I’m really looking for but I’m trying to link two values together.

Ex. This turning into

if Door.Orientation.Y == 0 then Door.LinearVelocity.VectorVelocity = Vector3.new(-2,0,0) end
if Door.Orientation.Y == 90 then Door.LinearVelocity.VectorVelocity = Vector3.new(0,0,2) end
if Door.Orientation.Y == 180 then Door.LinearVelocity.VectorVelocity = Vector3.new(2,0,0) end
if Door.Orientation.Y == -90 then Door.LinearVelocity.VectorVelocity = Vector3.new(0,0,-2) end

this (horrible example im aware it doesnt work exactly like this and im missing a lot)

0 = Vector3.new(-2,0,0)
90 = Vector3.new(0,0,2)
180 = Vector3.new(2,0,0)
-90 = Vector3.new(0,0,-2)

let me know if I’m being stupid, or if you know what I’m talking about

[BonesIsUseless (Bones)]

you could try a dictionary

local Vectors = {
    [0] = Vector3.new(-2,0,0),
    [90] = Vector3.new(0,0,2),
    [180] = Vector3.new(2,0,0),
    [-90] = Vector3.new(0,0,-2)
}

local Orientation = 90

print(Vectors[Orientation])

--> 0, 0, 2

local Orientation = Door.Orientation.Y

if Vectors[Orientation] then
  Door.LinearVelocity.VectorVelocity = Vectors[Orientation]
end

[jaminz4 (jamie)]

Thank you. I knew it was to do with a table I just hit a complete blank when trying to find out the method of actually doing it

[VisualPlugin (少・公・火・口ヶ口・火・公・少)]

I have a fèéling that CFrames’ trigonometric stuffs will work here:

local angle = 90
print(2 * CFrame.fromAxisAngle(Vector3.new(0,1,0), math.rad(angle)).LookVector)

Works with angles not in increments of 90 degrèés, but may require a bit more computing power.