Then you should be doing a background check on your team members? What is the bigger picture here?
You don’t seem to understand what obfuscation is. Obfuscation is simply making a script harder to reverse-engineer.
For instance
print(1)
can become
return(function(g,a,a)local j=string.char;local e=string.sub;local o=table.concat;local l=math.ldexp;local n=getfenv or function()return _ENV end;local m=select;local a=unpack or table.unpack;local k=tonumber;local function p(h)local b,c,d="","",{}local f=256;local g={}for a=0,f-1 do g[a]=j(a)end;local a=1;local function i()local b=k(e(h,a,a),36)a=a+1;local c=k(e(h,a,a+b-1),36)a=a+b;return c end;b=j(i())d[1]=b;while a<#h do local a=i()if g[a]then c=g[a]else c=b..e(b,1,1)end;g[f]=b..e(c,1,1)d[#d+1],b,f=c,c,f+1 end;return table.concat(d)end;local i=p('23S23U27523T23Z27523U26Y26W26B26C27223V27927923E25123U23Y27924823W27927G27524827827G27427H27927427R23X27Q27X275');local a=(bit or bit32);local d=a and a.bxor or function(a,c)local b,d,e=1,0,10 while a>0 and c>0 do local e,f=a%2,c%2 if e~=f then d=d+b end a,c,b=(a-e)/2,(c-f)/2,b*2 end if a<c then a=c end while a>0 do local c=a%2 if c>0 then d=d+b end a,b=(a-c)/2,b*2 end return d end local function c(b,a,c)if c then local a=(b/2^(a-1))%2^((c-1)-(a-1)+1);return a-a%1;else local a=2^(a-1);return(b%(a+a)>=a)and 1 or 0;end;end;local a=1;local function b()local f,e,c,b=g(i,a,a+3);f=d(f,138)e=d(e,138)c=d(c,138)b=d(b,138)a=a+4;return(b*16777216)+(c*65536)+(e*256)+f;end;local function h()local b=d(g(i,a,a),138);a=a+1;return b;end;local function f()local b,c=g(i,a,a+2);b=d(b,138)c=d(c,138)a=a+2;return(c*256)+b;end;local function p()local a=b();local b=b();local e=1;local d=(c(b,1,20)*(2^32))+a;local a=c(b,21,31);local b=((-1)^c(b,32));if(a==0)then if(d==0)then return b*0;else a=1;e=0;end;elseif(a==2047)then return(d==0)and(b*(1/0))or(b*(0/0));end;return l(b,a-1023)*(e+(d/(2^52)));end;local k=b;local function q(b)local c;if(not b)then b=k();if(b==0)then return'';end;end;c=e(i,a,a+b-1);a=a+b;local b={}for a=1,#c do b[a]=j(d(g(e(c,a,a)),138))end return o(b);end;local a=b;local function o(...)return{...},m('#',...)end local function l()local j={};local k={};local a={};local i={[#{"1 + 1 = 111";"1 + 1 = 111";}]=k,[#{"1 + 1 = 111";{485;27;655;337};"1 + 1 = 111";}]=nil,[#{{513;934;885;524};{619;244;354;249};"1 + 1 = 111";{289;463;951;76};}]=a,[#{"1 + 1 = 111";}]=j,};local a=b()local d={}for c=1,a do local b=h();local a;if(b==0)then a=(h()~=0);elseif(b==1)then a=p();elseif(b==3)then a=q();end;d[c]=a;end;i[3]=h();for i=1,b()do local a=h();if(c(a,1,1)==0)then local e=c(a,2,3);local g=c(a,4,6);local a={f(),f(),nil,nil};if(e==0)then a[3]=f();a[4]=f();elseif(e==1)then a[3]=b();elseif(e==2)then a[3]=b()-(2^16)elseif(e==3)then a[3]=b()-(2^16)a[4]=f();end;if(c(g,1,1)==1)then a[2]=d[a[2]]end if(c(g,2,2)==1)then a[3]=d[a[3]]end if(c(g,3,3)==1)then a[4]=d[a[4]]end j[i]=a;end end;for a=1,b()do k[a-1]=l();end;return i;end;local function j(a,b,g)a=(a==true and l())or a;return(function(...)local h=a[1];local c=a[3];local a=a[2];local a=o local d=1;local a=-1;local i={};local f={...};local e=m('#',...)-1;local a={};local b={};for a=0,e do if(a>=c)then i[a-c]=f[a+1];else b[a]=f[a+#{"1 + 1 = 111";}];end;end;local a=e-c+1 local a;local c;while true do a=h[d];c=a[1];if c<=3 then if c<=1 then if c==0 then local a=a[2]b[a](b[a+1])else b[a[2]]=a[3];end;elseif c>2 then local a=a[2]b[a](b[a+1])else do return end;end;elseif c<=5 then if c>4 then b[a[2]]=a[3];else b[a[2]]=g[a[3]];end;elseif c==6 then b[a[2]]=g[a[3]];else do return end;end;d=d+1;end;end);end;return j(true,{},n())();end)(string.byte,table.insert,setmetatable);
All that mess just to print 1. I won’t specify which obfuscator I used since I don’t want to give anyone any ideas. All it is doing is making the fact that it prints 1 less obvious.
It doesn’t break the game if used in another place.