How many arguments does a function takes

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#1

Greetings, developers.

I just wanted to know if it’s possible to know how many arguments does a function takes.

Example:

local foo = {
    ["Example_1"] = {id= 1, run= function(arg) print(arg) end},
    ["Example_2"] = {id= 2, run= function(arg, arg1) print(arg, arg1) end}
}

foo[input].run("Hello") -- ???
foo[input].run("Hello", "World") -- ???

My apologies if the post isn’t in the correct category, this is my first post.

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#2

You can take as many arguments as you want

local x = {}

for i = 1,5000 do
	table.insert(x,i)
end

function my(...)
	print(#{...})
end

my(table.unpack(x))  --prints 5000
#3

Okay, but how would I use the arguments? Like

function my(...)
    print(...[3])
end

???

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#4

the … let u take as many arguments as u want

function x(a,b,...)
	print(a,b,...)
end

x(4,"hi",12,true)  --prints 4,"hi",12,true
#5

… is just a little trickery with function arguments so that you can get any type of argument

local function foo(...)
   print(...) -- true, false, 12345
   local tbl = {...} --stored tuple arguments as an array with start to finish
   --useful for iterating over an unknown amount of objects and all you got are tuples
end

foo(true, false, 12345)
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#6

It was kinda hard, but I finally figured it out, thanks!

#7 
local function f(...)
	print(select("#", ...))
end

f("Hello world!", math.pi, math.huge) --3

No table manipulation required.

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