How table.find works?

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#1

So lets say I have a table

local s = {
	Common = 5,
	Uncommon = 10
}

print(table.find(s, "Common")) --> nil
-- However print(s["Common"]) will work

Can someone explain why and how to fix

#2

table.find looks for any value in a table, not a dictionary. As for that you can just call the dictionary’s value directly and it would work 1:1 like table.find. Just like in the example you gave.

1 Like
#3

table.find searches by value and returns the index where it was found:

-- Lua/Luau equivalent:

local s = {
	Common = 5,
	Uncommon = 10
}

for index, value in s do
   if value == "Common" then
       return index
   end
end

Basically, what @awry_y said

#4

Like? I dont understand

print(table.find(s, 5))

Wont work too
So I just have to do like this?

print(s["Common"])

Also I wonder if that above will error if there no such value (Like if table exists but there no common) or it will return nil

#5

Yes I know that this will work too, but it takes 4 lines

#6

It would just return nil. Though, if you try to use it then it would error. You can also set it like:

s.Common = 5

It won’t as 5 is the value of a key in the dictionary. You can’t access the value without a key. The key, is the name of the dictionary.

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#7

Oh, ok, I got it then ( I mean I was always using table[“Something”] to get value of it, but wondered how table.find works). Thanks

#8

I was showing what it does internally

1 Like
#9

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